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dexar [7]
3 years ago
7

Please help me answer #4, #5 and #6

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

4). The Washington Monument is 169.2-m tall.

Step-by-step explanation:

4). We know this because...

person     1.8       0.7

----------  = -----  = -------

Wash.        x       65.8

We then know to cross-multiply to get:  

1.8(65.8) = 0.7x

Which simplifies down to:

118.44 = 0.7x

x = 169.2

Answer:

5). The pond is 180ft wide.

Step-by-step explanation:

5). We know this because...

90       120

-----  = -------

135        x

We then know to cross-multiply to get:

90x = 120(135)

Which simplifies down to:

90x = 16200

x = 180

Answer:

6). The height of the clock tower is 13ft 9in.

Step-by-step explanation:

6). We know this because...

person       5.5         4

----------  =  --------  = -----

clock            x          10

We then know to cross-multiply to get:

5.5(10) = 4x

Which simplifies down to:

55 = 4x

x = 13.75 (13 ft 9 in)

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How to solve 9x^2+9x+2
Oksana_A [137]

Answer:

factoring: ( 3 x + 1 ) ( 3 x+ 2 )

expressing/equation: 9x²= 81x

81x + 9x + 2=

9x+81x=90x

90x + 2

Step-by-step explanation:

7 0
3 years ago
What is the distance between points S and U if S is 2, 1 and U is 6, 8
balandron [24]

The distance formula is:

D = sqrt((x2-x1)^2 + (y2-y1)^2)

D= sqrt ((6-2)^2 + (8-1)^2)

D = sqrt(4^2 + 7^2)

D = sqrt( 16 + 49)

D = sqrt(65)

D = 8.06

Rounded to the beat tenth = 8.1 units.

The answer is C. 8.1 units

4 0
3 years ago
Read 2 more answers
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
Is an Obtuse triangle a Acute triangle? Yes or no? And why or why not?
777dan777 [17]

Answer:

No, this is because the word obtuse is in the name obtuse triangle as well as it being a whole different angle than an acute angle. Obtuse angles are are greater than 90 degress but less than 180 while the acute angle is less than 90.

Step-by-step explanation:

5 0
3 years ago
What is 900,000*9,000
trasher [3.6K]

Answer:

8,100,000,000

Step-by-step explanation:

I used a calculator lol

4 0
3 years ago
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