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Paha777 [63]
3 years ago
12

A heavy rope, 40 ft long, weighs 0.8 lb/ft and hangs over the edge of a building 110 ft high. How much work is done in pulling t

he rope to the top of the building
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

Therefore the work done is 640 ft pound.

Step-by-step explanation:

Given that, a heavy rope 40 ft long, weighs 0.8 lb/ft.

Force = weight.

Let we pull x ft. Then the remain rope = (40-x)ft.

(40-x) ft it is variable.

The weight of (40-x) ft is =(40-x)0.8 lb

∴ Force =(40-x)0.8 lb

Work done = Force × displacement

                  = (40-x)0.8 Δx   [ displacement = Δx]

Therefore ΔW =(40-x)0.8 Δx

Since total rope is pulling up on the top of the building. Total displacement = 40 ft.

Total work done =\int_0^{40}(40-x)0.8 dx

                            =[32x-\frac{0.8x^2}{2}]_0^{40}

                            =[(32\times 40)-0.4(40)^2]

                            =640 ft pound.

Therefore the work done is 640 ft pound.

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(2x + 7y = -24<br>18x+y=12 solve by substitution​
const2013 [10]

Answer:

x = .87, or when approximated to a fraction, 27/31

y = -3.67, or when approximated to a fraction, -1287/350

Step-by-step explanation:

Lets start by rewriting out our equations

2x + 7y = -24

18x + y = 12

Lets solve for a y value; the second equation is easiest, as the y value has no coefficient (the number that is multiplied times a variable). To do this, lets move the 18x to the other side. Now our two equations look like:

2x + 7y = -24

y = -18x + 12

Next, lets plus the second equation into the first equation in regards to y.

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Now, lets solve!

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Then, combine your terms!

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Divide by (-124)!

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x = 27/31

Now that we know x, lets plug this back in to the first equation to find y!

2(27/31) + 7y = -24

1.74 + 7y = -24

7y = -25.74

y = -3.67, or when approximated to a fraction, -1287/350

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