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mafiozo [28]
2 years ago
12

John earned $45.90 during the summer break. He used 1/6 of the money to buy trading cards. Then, he used 3/5 of the remaining am

ount to buy a sketchbook, and also spends $4.50 on comic books. How much money does John have left after these purchases? $1180​
Mathematics
1 answer:
Fofino [41]2 years ago
8 0

The amount John have left after purchase is $10.8.

<h3 /><h3>Amount John have left</h3>

John  earned $45.90 during the summer break.

He used 1 / 6 of the money to buy trading card. Then he used the following amount to buy the trading card.

  • 1 / 6 × 45.90 = $7.65

Then, he used 3/5 of the remaining amount to buy a sketchbook, and also spends $4.50. Therefore, the total he spends can be computed as follows:

  • 3 / 5 × (45.90 - 7.65) + 4.50 = 22.95 + 4.50 = $27.45

So, He spent

  • $7.65 on trading cards
  • $22.95 on sketch book
  • $4.50 on comic book.

The amount he has left = 45.90 - 7.65 - 22.95 - 4.50 = $10.8

learn more on fraction here: brainly.com/question/3582128?referrer=searchResults

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Answer:

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Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

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Substitute,

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Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

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