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matrenka [14]
3 years ago
11

Can someone simplify (-5cd^(-4))(2cd^(2))^(2) i need the steps for this too not just the answer ty!

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Answer:

-20c^3

Step-by-step explanation:

(-20c^3)(d^4)/(d^4)

The d^4 cancles leaving you with -20c^3

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In this figure, 12.2% of the area is painted blue.
murzikaleks [220]
The answer is 4.27 if it’s the blue painted ones
5 0
2 years ago
Which expression is equal to 7(1+3) ?<br>7+21<br>7+3<br>1+21<br>7+4​
Marysya12 [62]

The right answer is first option: 7+21

Step-by-step explanation:

Given expression is;

7(1+3)

In mathematics, the term outside is multiplied by each term inside the bracket, therefore, in this expression;

7(1+3)\\7*1+7*3\\7+21\\

The given expression 7(1+3) is equals to 7+21.

The right answer is first option: 7+21

Keywords: multiplication, addition

Learn more about addition at:

  • brainly.com/question/9527632
  • brainly.com/question/9533500

#LearnwithBrainly

8 0
3 years ago
Please help with this question!! Will mark brainliest!! Thank you:)​
madam [21]

Answer:

I’m not good at algebra but I think that qx = -4 and qy = -7? I tried I’m not good at algebra.

Step-by-step explanation:

qy= -7 plus px= 3 equals -4

im not good at algebra

7 0
3 years ago
Jack and Diane were saving money to go to a rock n roll concert. They need at least $750 in order to go if you count their gas,
nataly862011 [7]

Answer:

\left\{\begin{array}{l}y\le 4x\\ \\x\ge 10\\ \\50x+25y\ge 750\end{array}\right.

Step-by-step explanation:

Let x represents the number of nights Jack worked and y represents the number of nights Diane worked.

1. The number of nights Diane is scheduled to work is no more than four times the number of nights Jack is scheduled to play. Then

y\le 4x

2. Diane will work at least 10 times before the concert. Then

x\ge 10

3. Jack earns $50 per night that he plays, then he earned $50x in x nights. Diane earns $25 each night she works, then she earns $25y in y nigths. They need at least $750, so

50x+25y\ge 750

4. We get the following set of constraints to model the problem:

\left\{\begin{array}{l}y\le 4x\\ \\x\ge 10\\ \\50x+25y\ge 750\end{array}\right.

4 0
3 years ago
Currently, each student in our school system is assigned a 6-digit (each
N76 [4]

Answer:

26,000,000 codes

Step-by-step explanation:

To find how many unique codes can be created, we just need to check how many possibilities there are for each letter or digit in the code.

Each letter has 26 possible values, and each digit has 10 possible values, so as we have 1 letter and 6 digits, the total number of unique codes are:

26 * 10 * 10 * 10 * 10 * 10 * 10 = 26,000,000 codes.

6 0
3 years ago
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