Answer:
Cubic polynomial or binomial
Step-by-step explanation:
3x^2y+5xy^2 is Cubic polynomial or binomial.
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
![\textsc{heya!}](https://tex.z-dn.net/?f=%5Ctextsc%7Bheya%21%7D)
we need to find the area of a circle with a radius of 21.
we also need a formula for this, which is
⇒ ![\bold{A=\pi r^2}](https://tex.z-dn.net/?f=%5Cbold%7BA%3D%5Cpi%20r%5E2%7D)
the known value is r, radius, 21.
after substituting the value into the formula, we obtain:
⇒ ![\bold{A=\pi (21)^2}](https://tex.z-dn.net/?f=%5Cbold%7BA%3D%5Cpi%20%2821%29%5E2%7D)
now we multiply the radius times itself:
⇒![\bold{A=\pi *441}](https://tex.z-dn.net/?f=%5Cbold%7BA%3D%5Cpi%20%2A441%7D)
<u>which can be</u> <u>written</u> <u>as</u>
<u />
<u>⇒</u>![\bold{A=441\pi}](https://tex.z-dn.net/?f=%5Cbold%7BA%3D441%5Cpi%7D)
and finally, multiply the values
⇒ ![\bold{A=1385.4\;units\;^2}](https://tex.z-dn.net/?f=%5Cbold%7BA%3D1385.4%5C%3Bunits%5C%3B%5E2%7D)
![\textsc{hopefully\:helpful}](https://tex.z-dn.net/?f=%5Ctextsc%7Bhopefully%5C%3Ahelpful%7D)
by: ![\textsc{$^da_nc^in_g$}](https://tex.z-dn.net/?f=%5Ctextsc%7B%24%5Eda_nc%5Ein_g%24%7D)
have a great rest of your day ahead ~ = )
Answer:
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.
Step-by-step explanation:
Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.
Now add 45 mins
Hours : Minutes
5: 40
<u> + 45</u>
<u> 5 : 85</u>
<u />
But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .
Hours : Minutes
1
5: 40
<u> + 45</u>
<u> 6 : 25</u>
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.
Set the function to equal zero:
![-x^2 - 5x + 50 = 0](https://tex.z-dn.net/?f=-x%5E2%20-%205x%20%2B%2050%20%3D%200)
To find the zeros, or solutions, to this problem, we will use the quadratic formula:
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Plug the values into the equation:
![a = -1, b = -5, c = 50](https://tex.z-dn.net/?f=a%20%3D%20-1%2C%20b%20%3D%20-5%2C%20c%20%3D%2050)
![x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm%5Csqrt%7B-5%5E2-4%28-1%29%2850%29%7D%7D%7B2%28-1%29%7D)
![x=\frac{5\pm\sqrt{25+200}}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm%5Csqrt%7B25%2B200%7D%7D%7B-2%7D)
![x=\frac{5\pm15}{-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm15%7D%7B-2%7D)
Solve for both plus and minus:
![\frac{5 + 15}{-2} = \frac{20}{-2} = -10](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%20%2B%2015%7D%7B-2%7D%20%3D%20%5Cfrac%7B20%7D%7B-2%7D%20%3D%20-10%20)
![\frac{5 - 15}{-2} = \frac{-10}{-2} = 5](https://tex.z-dn.net/?f=%5Cfrac%7B5%20-%2015%7D%7B-2%7D%20%3D%20%5Cfrac%7B-10%7D%7B-2%7D%20%3D%205)
![x = -10, x = 5](https://tex.z-dn.net/?f=x%20%3D%20-10%2C%20x%20%3D%205)
The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.
The answer is
'<span>
x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>