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Marrrta [24]
3 years ago
5

Find the 11th term of the geometric sequence 2, -6, 18, ...

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
R = a₂/a₁ = -3
a₁₁ = a₁r¹⁰ = 2×(-3)¹⁰ = 118,098
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Christina also plans on leaving her $10,000 invested for 20 years. Write an equation representing her investment’s value, y, aft
kaheart [24]

The required equation is y = 10000(1.0.25)^2x. The value of Christina’s investment after 20 years is $30,773.14

Compound interest

The interest accrued on a sum of money is known as interest. The formula for calculating the compound interest is expressed as:

y = y0(1+r/n)^nx

where

x is the time taken

r is the rate in decimal

n is the compounding time


Given the following

x = 20 years

n  2(semi annually)

r  = 5.7% = 0.057

Substitute

y = 10000(1+0.057/2)^2(20)
y = 10,000(1 + 0.0285)^40

y = 10000(1.0285)^40
y = 30,773.14

Hence the value of Christina’s investment after 20 years is $30,773.14

Learn more on compound interest here: brainly.com/question/24924853

4 0
2 years ago
Four times the sum of a number and 3 is equal to 7.
docker41 [41]

Answer:

4 times 1 plus 3 equals 7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the sum of the number 44+40 equals as the product of greatest common factor and another Sam
pychu [463]
WHAT???? well if your asking what's 44+40 its 84
5 0
3 years ago
Read 2 more answers
What is the ratio of the perimeter of ΔHKO to the perimeter of ΔFGO
slamgirl [31]

I think you meant to say the ratio of the areas (not perimeters). Also, HKO and FGO are not showing up, so it seems like a different problem. I'm going to answer the question you posted in the image attachments.

The triangle ABC has area 12 since

A = b*h/2 = 4*6/2 = 24/2 = 12

Triangle CEF has area 48 because

A = b*h/2 = 8*12/2 = 96/2 = 48

The ratio of the areas is found by dividing the area of ABC over the area of CEF (as the last box instructs) so we have 12/48 = 1/4

Therefore, the area of ABC is 1/4 that of the area of CEF

----------------------

In summary,

<h3>Answer for the first box: 12</h3><h3>Answer for the second box: 48</h3><h3>Answer for the third box: 1/4</h3>
3 0
3 years ago
A large industrial firm allows a discount on any invoice that is paid within 30 days. of all invoices, 10% receive the discount.
Daniel [21]
This situation has two outcomes: either an invoice is discounted or not. This two outcomes satisfy what we call a binomial distribution (note "bi" in binomial).

The binomial distribution tells us the probability that a randomly selected sample will have the outcome of success. In this case, we consider receiving the discount as the "success" outcome while not receiving it means "failure". The distribution takes the form:

P(X=x)= _{n}C_{x} p^{x}  q^{n-x}
where n is the total number of samples, x is the number of samples you'll expect to have a success outcome, p is the probability of success, q is the probability of failure, and nCx is the combination of n samples taken x at a time.

You have an inconsistency regarding the total number of samples by the way, but I will take the first mentioned sample of 15 as I answer (you can just follow through the same process for another value).

For the next step, let's digest the problem to get the needed variables.

The total number of samples, n, is equal to 15. The probability of success (receiving a discount), p, is 10% or 0.1, and the probability of failure (not receiving a discount) is 90% or 0.9.

For P(X=x), we need to find the probability that less than two of the samples have success outcomes therefore we need to find the probability that NO invoice will receive the discount plus the probability that ONE invoice will receive the discount. This is equivalent to saying
P(X\ \textless \ 2)=P(X=0)+P(X=1)

Calculating these probabilities we'll get:
P(X=0)= _{15}C_{0} (0.1)^{0} (0.9)^{15}=0.206
P(X=1)= _{15}C_{1} (0.1)^{1} (0.9)^{14}=0.343
P(X\ \textless \ 2)=P(X=0)+P(X=1)=0.206+0.343=0.549

ANSWER: The probability that fewer than 2 sampled invoices will receive the discount is 0.549 or 54.9%.
6 0
3 years ago
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