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Korvikt [17]
3 years ago
10

Using the figure below, tell if the triangles are congruent, and if so by what theorem?

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
A. Yes, they are congruent by SSS theorem.

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Ax+by=c solving for y
german

Answer:

ax + by = c \\  by = c - ax \\  \\ y =  \frac{c - ax}{b}  \\  \\ y =  \frac{c}{b}  -  \frac{ax}{b}

I hope I helped you^_^

8 0
3 years ago
Read 2 more answers
What is pi x 5 radius squared
Shalnov [3]

Hi!

5^2 is 25

so it's 25pi

or 78.54

Hope this helps!

6 0
3 years ago
Select the polynomial that is a perfect square trinomial.
alexdok [17]

Answer:

Option D. It's a perfect square trinomial.

Step-by-step explanation:

(a) 36x² - 4x + 16

= (6x)² - 2(2x) + (4)²

It's not a perfect square trinomial

(b) 16x² - 8x + 36

= (4x)² - 2x(4x) + (6)²

It's not a perfect square trinomial

(c) 25x² + 9x + 4

= (5x)² + 2(\frac{9}{2}x) + (2)²

It's not a perfect square trinomial

(d) 4x² + 20x + 25

= (2x)² + 2(10x) + (5)²

= (2x+5)²

It's a perfect square trinomial.

8 0
3 years ago
Read 2 more answers
3. Aşağıda verilen çıkarma işleminde bazı rakamların yerine semboller kullanılmıştır.
babymother [125]

Answer:

thr answers are A and D of the question

5 0
3 years ago
How many revolutions will a car wheel of diameter 22 in. make as the car travels a distance of one mile
Marianna [84]

It would be take upto 999 revolutions.

<em>Let try to solve it,</em>

Let n represent number of revolutions.

We are asked to find the number of revolutions it will take for a car wheel of diameter 30 in. to travel a distance of one mile.

1 mile = 63360 inches.

We will use circumference of circle formula to solve our given problem.

Circumference = pi*d , where, D represents diameter of circle.

Now, we will set the product of n and circumference of circle equal to 63360 inches as:

pi*22*n= 63360

n= 63360*7/ 22*22

n= 443520/444

n= 998.91

Therefore It would be take upto 999 revolutions.

Learn more about Circumference of circle on:

brainly.com/question/18571680

#SPJ4

8 0
2 years ago
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