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2 years ago

Help help math math please pelsss

Mathematics

1 answer:

vampirchik [111]2 years ago

5 0

Answer:

116°

Step-by-step explanation:

together both angles equal 180 because they are on a straight line and are opposite of each other.

180 - 64 = 116

I hope this helps!!

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Mark and John share the sum of $40 in ratio 2:3 how much does John get

lara [203]

Answer:

John gets 24 dollars

Step-by-step explanation:

Divide 40 into 5 because 2+3 equals 5.

Each "section" equals 8. Now, multiply that by 3(John's section)

You get 24.

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2 years ago

The difference between any two square consecutive number is 20. find the number ?

sergij07 [2.7K]

Answer:

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Step-by-step explanation:

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1 year ago

How was sharecropping used to manipulate blacks in the south?

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Sharecropping is a type of farming in which families rent small plots of land from a landowner in return for a portion of their crop, to be given to the landowner at the end of each year. Different types of sharecropping have been practiced worldwide for centuries, but in the rural South, it was typically practiced by former slaves. With the southern economy in disarray after the abolition of slavery and the devastation of the Civil War, conflict arose during the Reconstruction era between many white landowners attempting to reestablish a labor force and freed blacks seeking economic independence and autonomy.

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3 years ago

Find the difference. Simplify the

Novay_Z [31]

Step-by-step explanation:

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2 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago