C) yes the corresponding angles are congruent
Answer:
(c) 24 (d) 2 -4 (e) 22 2 1.25 0
Step-by-step explanation:
Problem 1.1 (10 Points) Let 21 2j, and 23 j. Find the value of each of the following 3 4j, 22 expressions and give your answers in rectangular form z t jy. (a) 132122 (b) 321 421 (c) (21)3 (Note that superscript denotes conjugation.) 222 21 (d) 22 (e) 2223 Problem 1.2 (10 Points) (a) Find real numbers r and y such that 5z -3y j(5y z) 4. (b) Show that any complex number z can also be expressed as z e 2"* k 0, 1,2, 3. Problem 1.3 (10 Points) Express each of the following complex numbers in polar form. a) 2 2V3 (c) 1 j j2 7 4j (d) 3-2j (e) Problem 1.4 (10 Points) Use the results from Problem 1.2 (b) above to find all roots of the following complex numbers and plot your results in the complex plane. (a) 1 (Hint: there are 5 different answers and one is 2 (b) 23 (1 -j) (Hint: there are 3 different answers. (c) 24 (d) 2 -4 (e) 22 2 1.25 0
In the original expression there are 6 terms in the simplyfied one there are only 3
In the simplified expression coefficient of x is (-2)
He has 12 green marbles. 4+9=13 and 39/13=3 so 4x3=12. to check, we can do 9x3=27 as well and add our results. 12+27=39 so we know we are correct.
The shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is a rectangle.
<h3>What is the explanation for the submission above?</h3>
Note that the Area of the cross-section = 16 sqrt(2) = 22.63 sq. units. The justification for this is the properties of the Cubes.
- The top face ABCD is parallel and congruent to the bottom face EFGH....(A)
- Also, sides AE and CH are perpendicular to faces ABCD and EFGH ....(B)
Mathematically, we can righty state that Diagonals AC and EH are congruent .....(C)
Given the justification by (A), congruent top and bottom faces, let us look at the cross-section ACHE.
AC is congruent and parallel to EH (A) & (C)
EA & HC are perpendicular to AC (B)
Hence, the quadrilateral ACHE is a rectangle.
Step 2
Length of diagonal AC = sqrt(4^2+4^2) = 4 sqrt(2) Pythagoras theorem.
AE = CH = DG = 4 We state this because the of the properties of cube, all sides equal;
Hence, the Area of ACHE = 4* 4sqrt(2) = 16 sqrt(2)
= 22.63 sq. units
Learn more about Cuboids at:
brainly.com/question/1972490
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