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labwork [276]
2 years ago
5

Tom climbs 100 meters up a mountain in 40 minutes. How far up is he likely to climb in 160 minutes?​

Mathematics
2 answers:
seraphim [82]2 years ago
5 0

Answer:

400 meters

Step-by-step explanation:

We can write a ratio.

100m : 40 min

Multiply both sides by 2

400 m : 160 min

Tom is likely to climb 400 meters in 160 minutes

Hope this helps :)

Naddik [55]2 years ago
3 0

Answer:

400 meters

Step-by-step explanation:

Just multiply both by 4 since 40 x 4 = 160!

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In quadrilateral QRST, Angle R S T measures (5x+15)°. Angle TQR measures (4x+3)°. Circle P is inscribed with quadrilateral Q R S
Assoli18 [71]

Answer:

105degrees

Step-by-step explanation:

Using the theorems that states that the sum of the opposite side of the quadrilateral is 180degrees, hence;

<RST + <TQR = 180

5x+15 + 4x+ 3 = 180

9x + 18 = 180

9x = 180 - 18

9x = 162

x = 162/9

x = 18

Since <RST = 5x+15

<RST = 5(18) + 15

<RST = 90 + 15

<RST = 105degrees

Hence the measure of <RST is 105degrees

7 0
3 years ago
Read 2 more answers
Yard
Lana71 [14]

Answer:

31

Step-by-step explanation:

3 0
3 years ago
An arithmetic sequence has this recursive formula:
ankoles [38]

Hello!


The recursive rule for an arithmetic sequence: a_{n} = a_{n-1} + d.

The explicit rule for an arithmetic sequence: a_{n}=a_{1} +d(n-1).


a_{n} is the value you are trying to find, or simply the answer. :)

d is the common difference of the sequence.

a_{1} is the first term of the sequence.


Given, a_{1} = 8 and a_{n}=a_{n-1} - 6...

The common difference is -6, and the first term is 8.


Plug these values into the explicit rule for an arithmetic sequence, you get:

a_{n}=8+(-6)(n-1).


Therefore, the answer is A, a_{n}=8+(n-1)(-6).


If you wondered why, a_{n}=8+(-6)(n-1) is equal to a_{n}=8+(n-1)(-6), the Commutative Property of Multiplication states that when two numbers are multiplied together, the answer is the same regardless of the order of the numbers, which makes a_{n}=8+(-6)(n-1) and a_{n}=8+(n-1)(-6) equal to each other.

4 0
3 years ago
Read 2 more answers
Phoenix is a hub for a large airline. Suppose that on a particular day, 8000 passengers arrived in Phoenix on this airline. Phoe
Afina-wow [57]

Answer:

Step-by-step explanation:

Hello!

In a day a total of n= 8000 passangers arrived to Phoenix.

1400 of these passangers <u>final destination was Phoenix. (A)</u>

The remaining 6600 passangers were all taking c<u>onnection flights to other cities. (B)</u>

Due to several flights being late, 430 connecting passengers <u>missed their connecting flight and were delayed in Phoenix. (C)</u>

Of these 430 delayed passengers, 75 were <u>delayed overnight. (D)</u>

If there was one passenger chosend at random:

a) You have to calculate the probability of this passegners final destination to be Phoenix. Symbolically: P(A)

To calculate this probability you have to divide the number of  passengers whose final destination was Phoenix by the total number of pasengers:

P(A)= \frac{1400}{8000} = 0.175

b) The passangers whose final destination was not phoenix are those taking connection flights, the probability of this event, called B, is calculated dividing the total of connecting passengers by the total of passengers:

P(B)= \frac{6600}{8000}= 0.825

c) You need to calculate the probability of "the passenger was connecting and missed the connecting flight"

The amount of passengers that fit this situation are 430 of 8000, so the probability is calculated as:

P(C)= \frac{430}{8000} = 0.05375 ~= 0.054

d) Of all 6600 connecting passengers, only 430 missend the flight wich means that 6170 took the connecting flight, the probability of this event "E" is

P(E)= \frac{6170}{8000}= 0.771

e) The passenger either had Phoenix as a final destination or was delayed overnight, symbolically:

P(A∪D) = P(A) + P(D) - P(A∩D)

The probability of the passenger being delayed overnight is:

P(D)= \frac{75}{8000} = 0.009

The events "A" and "D" are mutually exclusive, this means that they cannot occur both at the same time, so their intersection is void, P(A∩D)= ∅

Then

P(A∪D) = P(A) + P(D) = 0.175 + 0.009= 0.184

f) If using the same data we turn this event into a binomial variable were our success will be "the passenger missed his flight and was delayed overnight" with probability p=0.009 and the sample n= 50

Let's say that the airline should be worried if more than half of the surveyed passengers were delayed overnight then:

P(X>25)= 1 - P(X ≤ 25) = 1 - 0.999999 = 0.000001

The probability of most of the surveyed passenger were delayed overnight is too low so the company should not be worried.

I hope it helps!

5 0
3 years ago
Assume that the probability of a boy being born is the same as the probability of a girl being born. Find the probability that a
maxonik [38]
We want the probability of at least 1 girl. Lets look at the probability of the opposite: all boys. There is a 1/2 chance at each birth that the child will be a boy, so for that to happen 3 times in a row, the odds are 1/2 * 1/2 * 1/2 = 1/8.
Any other possible composition of the family meets the condition laid down, so the odds of at least 1 girl are 1-1/8 = 7/8.
5 0
3 years ago
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