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yulyashka [42]
3 years ago
8

Triangle a' B' c' is dilation of triangle abc about point p. Is this a reduction or enlargement​

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0

Enlargement

Hope this helps :)

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Inga [223]
Your answer is 127.5 is 250% of 51
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The figures below are similar. The labeled sides are corresponding.
Leno4ka [110]
I need the points sorry
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(13 points) (geometry) plz help last question and its due at midnight
Nezavi [6.7K]

Answer:

a. Second Option

b. Second Option

c. Third Option

d.ASA

Step-by-step explanation:

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Triangle ABC is an isosceles triangle in which side
Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula, we get

AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5

BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}

AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5

Now,

Perimeter of triangle ABC = AB + BC + AC

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So, perimeter of triangle ABC is 10+\sqrt{10} units.

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marysya [2.9K]

Answer:

\huge x >  \frac{7}{3}  \\

Step-by-step explanation:

8( \frac{1}{2} x -  \frac{1}{4} ) > 12 - 2x \\

<u>Expand the terms in the bracket</u>

That's

8( \frac{1}{2} x) - 8( \frac{1}{4} ) > 12 - 2x \\ 4x - 2 > 12 - 2x

Move -2x to the other side of the inequality

4x + 2x - 2 > 12 \\ 6x - 2  > 12

<u>Move - 2 to the other side of the inequality</u>

6x > 12 + 2 \\ 6x > 14

Divide both sides by 6

\frac{6x}{6}  >  \frac{14}{6}  \\

We have the final answer as

x >  \frac{7}{3}  \\

Hope this helps you

5 0
3 years ago
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