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iris [78.8K]
3 years ago
6

Forty slips are placed into a hat, each bearing a number 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10, with each number entered on four slip

s. Four slips are drawn from the hat at random and without replacement. Let be the probability that all four slips bear the same number. Let be the probability that two of the slips bear a number and the other two bear a number . What is the value of
Mathematics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

a) 162

Step-by-step explanation:

trust

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What is the greatest factor of 49 that is a prime number
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7.

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Read 2 more answers
PLEASE HELP ASAP WILL MEDAL BRAINLIEST
Naddik [55]
Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A 

A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11

B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29


Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18

5 0
3 years ago
Someone please help me to solve this questions...​...
wlad13 [49]

Answer:

1) Event A = 2/3

   Event B = 1/2

2) 1/2

Step-by-step explanation:

1)

Event A :

No. we need on dice = 4

Total numbers on dice = 6

Hence sample space of the event = 6

P( getting 4) = 4/6 = 2/3

Event B :

A coin has a head & a tail.

Hence sample space of the event = 2

But as we need tail only ,

P ( getting Tail ) = 1/2   [ if only tossed once ]

2)

Total numbers on a die = 6

Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )

Sample space of this event = 6

P (getting an odd number) = 3/6 = 1/2

6 0
3 years ago
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