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2 years ago

10

A plane is scheduled to complete a 1,792-mile flightin 3.5 hours. In order to complete the trip on time, what should be the plan

e's average rate of speed?
someone please help

1 answer:

deff fn [24]2 years ago

5 0

Answer:

512 mph

Step-by-step explanation:

The relevant relation is ...

speed = distance/time

speed = 1792 mi/(3.5 h) = 512 mi/h

The plane's average rate of speed should be 512 miles per hour.

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Pleaseee helppp with thisss asappp

Hoochie [10]

We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is ${\bf (x-h)^{2}+(y-k)^{2}=r^{2}}$ where <em>(h,k)</em> is the centre of the circle and radius is <em>r</em> . Proceeding further ;

${:\implies \quad \sf x^{2}+12y+22x+y^{2}-167=0}$

Collecting <em>x</em> terms , y terms and transposing the constant to RHS ;

${:\implies \quad \sf (x^{2}+22x)+(y^{2}+12y)=167}$

Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .

${:\implies \quad \sf (x^{2}+22x+121)+(y^{2}+12y+36)=167+121+36}$

${:\implies \quad \sf (x+11)^{2}+(y+6)^{2}=324\quad \qquad \{\because a^{2}+2ab+b^{2}=(a+b)^{2}\}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{\{x-(-11)\}^{2}+\{y-(-6)\}^{2}=(18)^{2}}}}$

On comparing this with the standard equation , we got our centre at <em>(-11,-6)</em> and radius is <em>18 units </em>

8 0

1 year ago

the sum of 2 consecutive integers is less than 55.the pair of integers sum are 26 and 27. true or false?

son4ous [18]

X + x + 1 < 55
2x + 1 < 55
Subtract 1 from both sides
2x < 54
Divide both sides by 2
x < 27
The integer less than 27 is 26.
26 + 27 < 55. True

6 0

3 years ago

Find the slope and y intercept of the line represented by each table

zvonat [6]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

(1)

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 22) and (x₂, y₂ ) = (4, 32) ← 2 ordered pairs from the table

m = $\frac{32-22}{4-2}$ = $\frac{10}{2}$ = 5, thus

y = 5x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (6, 42), then

42 = 30 + c ⇒ c = 42 - 30 = 12

Thus Table 1 has slope = 5 and y- intercept = 12

(2)

Using (x₁, y₁ ) = 2, 15) and (x₂, y₂ ) = (1,8) ← 2 ordered pairs from the table

m = $\frac{8-15}{1-2}$ = $\frac{-7}{-1}$ = 7, thus

y = 7x + c ← is the partial equation

To find c substitute (3, 22) into the partial equation

22 = 21 + c ⇒ c = 22- 21 = 1

Thus Table 2 has slope = 7 and y- intercept = 1

7 0

3 years ago

Distance the points Q(-1,-7) and H(-4,1) in coordinate plane

Airida [17]

Answer:

hope you know Distance formula

Step-by-step explanation:

Think the answer is

$\sqrt{73}$

units

4 0

1 year ago

suppose that $17,000 is deposited for six years at 5% APR. Calculate the interest earned if interest is compounded quartly . Rou

Lapatulllka [165]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$17000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &6
\end{cases}
\\\\\\
A=17000\left(1+\frac{0.05}{4}\right)^{4\cdot 6}\implies A=17000(1.0125)^{24}$

the earned interest will then be A - P, namely A - 17000.

5 0

2 years ago