Guys cqn you help me please

Mathematics

2 answers:

svp [43]2 years ago

5 0

yan po answer

#CARRYONLEARNING

LOVE U ALL

nikklg [1K]2 years ago

3 0

y = x + 2.
Let x be 0. Then y = 2.
Let x be 4, then y = 6.
Let y be 0, then x = -2.
Let A be (0, 2), B be (4, 6), C be (-2, 0).
Plotting the points on a given graph, we get the graph as shown in the picture.

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$