-3X+4=16
Subtract 4 from each side.
-3x+4-4=16-4
-3x=12
Divide each side by -3.
x=-4
I hope this helps!
Answer:
Option B is correct.
Step-by-step explanation:
Given
R = {-1, 0, 1, 2, 4, 5}
S = {4, 5, 6}
To determine
R ∩ S = ?
The intersection of two given sets R and S is the largest set which consists of all the elements that are common to both sets.
Thus, we conclude that:
R = {-1, 0, 1, 2, 4, 5}
S = {4, 5, 6}
The intersection of two given sets R and S:
R ∩ S = {4, 5}
Hence, option B is correct.
<u>Step-by-step explanation:</u>
To prove:
![\cos 3x=\cos^3x-3\sin^2 x\cos x](https://tex.z-dn.net/?f=%5Ccos%203x%3D%5Ccos%5E3x-3%5Csin%5E2%20x%5Ccos%20x)
Identities used:
......(1)
........(2)
.......(3)
Taking the LHS:
![\Rightarrow \cos 3x=\cos (x+2x)](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ccos%203x%3D%5Ccos%20%28x%2B2x%29)
Using identity 1:
![\Rightarrow \cos (x+2x)=\cos x\cos 2x-\sin x\sin 2x](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ccos%20%28x%2B2x%29%3D%5Ccos%20x%5Ccos%202x-%5Csin%20x%5Csin%202x)
Using identities 2 and 3:
![\Rightarrow \cos x(\cos ^2x-\sin^2 x)-\sin x(2\sin x\cos x)\\\\\Rightarrow \cos^3x-\sin^2x\cos x-2\sin^2 x\cos x\\\\\Rightarrow \cos^3x-3\sin^2x\cos x](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ccos%20x%28%5Ccos%20%5E2x-%5Csin%5E2%20x%29-%5Csin%20x%282%5Csin%20x%5Ccos%20x%29%5C%5C%5C%5C%5CRightarrow%20%5Ccos%5E3x-%5Csin%5E2x%5Ccos%20x-2%5Csin%5E2%20x%5Ccos%20x%5C%5C%5C%5C%5CRightarrow%20%5Ccos%5E3x-3%5Csin%5E2x%5Ccos%20x)
As, LHS = RHS
Hence proved
Answer:
(19,-14)
Step-by-step explanation:
let endpoint 2 be x2,y2
then apply mid point formula
x=(x1+x2)/2
y=(y1+y2)/2