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Nuetrik [128]
3 years ago
8

There is only one checkout line and the average service time is 5 minutes per customer. There are 3 people in the queue ahead of

you. What is the probability that your wait time will exceed 7 minutes?
Mathematics
2 answers:
insens350 [35]3 years ago
6 0

Answer:

62.7%

Step-by-step explanation:

This is an example of a Poisson process:

  • Events are independent
  • The average rate is constant
  • Events cannot happen simultaneously

Using a Poisson distribution, the probability that the wait time T will exceed a certain time t is:

P(T > t) = e^(-events/time × t)

The average wait time per customer is 5 minutes, so the expected wait time for 3 customers is 15 minutes.

Given that t = 7 min and event/time = 1 / 15 min:

P(T > 7) = e^(-1/15 × 7)

P(T > 7) = 0.627

There is a 62.7% probability that your wait time will exceed 7 minutes.

White raven [17]3 years ago
5 0

Answer:

The probability is 100% because 3*5 is 15, since 5 is the average time and 3 customers are already there.

Step-by-step explanation:

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Step-by-step explanation:


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Here, I'll do the first one for you.
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Which expressions show the expanded form for 200.06? Choose all answers that are correct. A. 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/
saveliy_v [14]

Answer:

Therefore,

Correct options are

A)  2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

Step-by-step explanation:

Given:

Number is

200.06

For option A)

2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

= 200 + 0 + 0 + 0.06

= 200.06

Which is CORRECT.

For option B)

2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000

= 200 + 0 + 0 + 0.006

=200.006

Which is INCORRECT.

For option C)

2 × 100 + 6 × 1/10

= 200 + 0.6

= 200.6

Which is INCORRECT.

For option D)

2 × 100 + 6 × 1/100

= 200 + 0.06

= 200.06

Which is CORRECT.

Therefore,

Correct options are

A)  2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

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Step-by-step explanation:

Ill do it

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