Ask question

Ask question

All categories

3 years ago

8

There is only one checkout line and the average service time is 5 minutes per customer. There are 3 people in the queue ahead of

you. What is the probability that your wait time will exceed 7 minutes?

2 answers:

insens350 [35]3 years ago

6 0

Answer:

62.7%

Step-by-step explanation:

This is an example of a Poisson process:

Events are independent
The average rate is constant
Events cannot happen simultaneously

Using a Poisson distribution, the probability that the wait time T will exceed a certain time t is:

P(T > t) = e^(-events/time × t)

The average wait time per customer is 5 minutes, so the expected wait time for 3 customers is 15 minutes.

Given that t = 7 min and event/time = 1 / 15 min:

P(T > 7) = e^(-1/15 × 7)

P(T > 7) = 0.627

There is a 62.7% probability that your wait time will exceed 7 minutes.

White raven [17]3 years ago

5 0

Answer:

The probability is 100% because 3*5 is 15, since 5 is the average time and 3 customers are already there.

Step-by-step explanation:

You might be interested in

Based on the line of best fit, how much money would a company most likely spend on advertising if the company's yearly revenue w

Ulleksa [173]

Answer:

I dont understand the qustion? did you answer it?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve for x: 3x − 24 = 81

LenKa [72]

3x - 24 = 81

Add 24 to each side.

3x - 24 + 24 = 81 + 24

3x = 105

Divide each side by 3.

(3x)/3 = 105/3

x = 35

Answer: x = 35

5 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

3 years ago

Write the relation as a set of ordered pairs.

ankoles [38]

Answer:

option B is the answer.

7 0

3 years ago

Is (-a + b)² = a² - 2ab + b² right or wrong, and why?

antiseptic1488 [7]

Answer:

$\huge\boxed{\sf Right.}$

Step-by-step explanation:

$(-a+b)^2$

Let's apply the formula (x+y)² = x² + 2xy + y²

Here, x = -a and y = b

So,

= (-a)² + 2(-a)(b) + (b)²

= a² - 2ab + b²

Hence, it has been proved that (-a + b)² = a² - 2ab + b².

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

6 0

2 years ago