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Nuetrik [128]
3 years ago
8

There is only one checkout line and the average service time is 5 minutes per customer. There are 3 people in the queue ahead of

you. What is the probability that your wait time will exceed 7 minutes?
Mathematics
2 answers:
insens350 [35]3 years ago
6 0

Answer:

62.7%

Step-by-step explanation:

This is an example of a Poisson process:

  • Events are independent
  • The average rate is constant
  • Events cannot happen simultaneously

Using a Poisson distribution, the probability that the wait time T will exceed a certain time t is:

P(T > t) = e^(-events/time × t)

The average wait time per customer is 5 minutes, so the expected wait time for 3 customers is 15 minutes.

Given that t = 7 min and event/time = 1 / 15 min:

P(T > 7) = e^(-1/15 × 7)

P(T > 7) = 0.627

There is a 62.7% probability that your wait time will exceed 7 minutes.

White raven [17]3 years ago
5 0

Answer:

The probability is 100% because 3*5 is 15, since 5 is the average time and 3 customers are already there.

Step-by-step explanation:

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Mnenie [13.5K]

<span>If there has to be 2 men and 2 women, we know that we must take a group of 2 men out of the group of 15 men and a group of 2 women out of the group of 20 women. Therefore, we have:

(15 choose 2) x (20 choose 2)


(15 choose 2) = 105

(20 choose 2) = 190

190*105 = 19950

Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>

 

<span>If there has to be 1 man and 3 women, we know that we must take a group of 1 man out of the group of 15 men and a group of 3 women out of the group of 20 women. Therefore, we have:

(15 choose 1) x (20 choose 3)


(15 choose 1) = 15

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15*1140 = 17100

Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>

 

<span>We now find the total outcomes of having a group with 4 women.

We know this is the same as saying (20 choose 4) = 4845</span>

Therefore, there are 4845 ways to have a group of 4 with 4 women.

 

We now add the outcomes of 2 women, 3 women, and 4 women and get the total ways that a committee can have at least 2 women.

 

19950 + 17100 + 4845 = 41895 ways that there will be at least 2 women in the committee


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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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