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Nuetrik [128]
3 years ago
8

There is only one checkout line and the average service time is 5 minutes per customer. There are 3 people in the queue ahead of

you. What is the probability that your wait time will exceed 7 minutes?
Mathematics
2 answers:
insens350 [35]3 years ago
6 0

Answer:

62.7%

Step-by-step explanation:

This is an example of a Poisson process:

  • Events are independent
  • The average rate is constant
  • Events cannot happen simultaneously

Using a Poisson distribution, the probability that the wait time T will exceed a certain time t is:

P(T > t) = e^(-events/time × t)

The average wait time per customer is 5 minutes, so the expected wait time for 3 customers is 15 minutes.

Given that t = 7 min and event/time = 1 / 15 min:

P(T > 7) = e^(-1/15 × 7)

P(T > 7) = 0.627

There is a 62.7% probability that your wait time will exceed 7 minutes.

White raven [17]3 years ago
5 0

Answer:

The probability is 100% because 3*5 is 15, since 5 is the average time and 3 customers are already there.

Step-by-step explanation:

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Step-by-step explanation:

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natural numbers will ____ be whole numbers. Integers will ___ be natural numbers. Irrational numbers will ___ be real numbers. R
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Step-by-step explanation:

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3 years ago
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igor_vitrenko [27]

Answer:

Their weekly sales would have to be $10,000 before they can be earning the same amount for the week

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