<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
Answer:
7.D) 107°
8. A) 123°
Step-by-step explanation:
To find the correct measurement of the angel the sum of the interior angels needs to equal 360°. Angels where the lines intersect with the circle would be both 90°. ( If that makes sense.)
90°+90°=180
180°+73°= 253°
360°-253°= 107°
The same for the second one. (those two angles would also be 90° each.)
90°+90°=180°
180°+57°=237°
360°-237°=123°
Step-by-step explanation:
So if you multiply both the numerator and denominator by the same number, you get the initial number. Your goal here is to get the same denominator so that you can solve the problem easily! hope it helped!
35 bc I think because 49 bc is not
