(1/4)^-2 - (5^0 x 2) x 1^-1 =
(4/1)^2 - (1 x 2) x 1 = 16-2 = 14
If you raise something to the power of -2, swap numerator and denominator and remove the minus.
So (1/4)^-2 = 4^2 = 16
Also 1^-1 is just 1, not -1.
Divide both sides by 2
p + 1 = 16/2
Simplify 16/2 to 8
p + 1 = 8
Subtract 1 from both sides
p = 8 - 1
Simplify 8 - 1 to 7
<u>p = 7</u>
Answer:
4. 2. 2. 4. 5. 5. 10. 15.
Step-by-step explanation:
x−1 x+1. = ∞. 2. All the vertical asymptotes of the function f(x) = x2 − 1 x3 − 9x are at. Answer: x = 0 and x = ±3. Solution: Write f(x) = g(x) h(x) ... x→a− f(x) or lim x→a+ f(x) is ±∞. For a = 0, lim x→0+ f(x)=+∞. For a = 3, lim x→3+ f(x)=+∞. ... 5. 10. Which of the following gives the graph of f (x)
Answer:
Consider the expression 
. q is called the quotient, a is is the dividend and b is the divisor.
Since q is a multiple of 6, then q has the form 
for some integer k.
Since a is a multiple of 9, then a has the form 
for some integer s.
Since b is a factor of 12, then if 12 can be expressed of the form 
, for c an integer. Then b has the form 
Replacing the preview expression in the initial expression we obtain:
Then 
is a equation to Isabel's problem.
