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ZanzabumX [31]
2 years ago
12

117 IS 7.3 PERCENT OF WHAT NUMBER?

Mathematics
1 answer:
DedPeter [7]2 years ago
3 0
ANSWER: 8.541

8.541 * 7.3% = 117
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Your answer would be 3 boxes are filled every 4 minutes
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4 years ago
The circle graphs show the percentage of men and women from Country X who consider owning a home an important part of adult life
morpeh [17]

Answer: a) 76 : 24

              b) 24 : 76

Step-by-step explanation: <u>Odds</u> describe the possibility an event will occur, i.e., is the ratio of an event being successful with the chance of an event failing. It can be in favor or against:

  • <u>Odds</u> <u>in</u> <u>favor</u> is expressed as: favor=\frac{favorable}{unfavorable};
  • <u>Odds</u> <u>against</u> is expressed as: against=\frac{unfavorable}{favorable};

a) Odds in favor

favor=\frac{76/100}{24/100}

favor=\frac{76}{24}

or

favor = 76 : 24

Odds in favor of a man agreeing owning a house is an important part of adult life is 76 : 24.

b) Odds against

against=\frac{24/100}{76/100}

against=\frac{24}{76}

or

against = 24 : 76

Odds against of a man agrreing that owning a house is an important part of adult life is 24 : 76

8 0
3 years ago
Please help me with this one
klasskru [66]
The value of X would be -2

The equation to find the value for all X values is X+22=Y

So, because Y is 20 we plug that information into the equation

Our new equation is now X+22=20

Now we solve for X

X+22=20
-22 -22

In the end it leaves us with X=-2

Hope this helps!
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3 years ago
Does anyone want to talk
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Answer:

yo

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
This high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards
liberstina [14]

Answer:

Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.

The school decided to cover the semicircles with grass to create a space for stretching and other activities.

To Find: area of one of the semicircles at either end of the track

How many square yards of grass will the school need to cover the entire circle?

Solution:

Diameter of semicircle = 70 yards

Radius of semicircle = 70/2 = 35 yards

Area of semicircle at one end = (1/2)πr²

= (1/2)(22/7)35²

= 1,925 sq yards

area of one of the semicircles at either end of the track = 1,925 sq yards

square yards of grass will the school need to cover the entire circle

= 2 x   1,925

= 3850 sq yards

distance around one of the semicircles at either end of the soccer field = πr  = (22/7) 35 = 110 yards

distance around the inner lane of the track  = 100 + 100 + 110 + 110

= 420 yards

Please Mark as Brainliest

Hope this Helps

4 0
3 years ago
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