Answer:
The adult ticket costs $18 and the children ticket costs $13.
Step-by-step explanation:
Let the price of the adult ticket be a.
Let the price of the children ticket be c.
Three adults and four children must pay $106. This implies that:
3a + 4c = 106 _______(1)
Two adults and three children must pay $75. This implies that:
2a + 3c = 75 ________(2)
We have two simultaneous equations:
3a + 4c = 106 _____(1)
2a + 3c = 75 ______(2)
Multiply (1) by 2 and (2) by 3 and subtract (1) from (2):
6a + 9c = 225
- <u>(6a + 8c = 212)</u>
c = $13
Put this value of c in (2):
2a + 3*13 = 75
2a + 39 = 75
=> 2a = 75 - 39
2a = 36
a = 36/2 = $18
Therefore, the adult ticket costs $18 and the children ticket costs $13.
For this case we must raise an inequality.
We have "d" dollars initially and they are spent 12. Then:

At least 51 dollars remain, then, the sign of inequality is greater or equal in favor of the expression
, that is:

Resolving:

There are at least 63 dollars left in the account.
Answer:

What is the binomial raised to? you can’t do this problem without it
Answer:
9 and a half
Step-by-step explanation:
the fewest number is 9.5 because thats the exact amount in hallways that he needs
If your substituting the points (-1,4) the answer would be 2=2