I think its 2 (not sure though just a guess)
We know that
[volume of rectangular prism]=L*W*h
L= 6 in prism A
volume of rectangular prism A=6*w*h
L=6*(1/2)------> L=3 in prism B
volume of rectangular prism B=3*w*h
so
volume of rectangular prism B=[volume of rectangular prism A]/2
the answer is
Volume of B is 1/2 volume of A
Answer:
Area of the shaded region = 1.92 cm²
Step-by-step explanation:
From the picture attached,
Area of the shaded region = Area of the sector OMN - Area of the triangle OMN
Area of sector OMN = 
Here, θ = Central angle of the sector
r = radius of the sector
Area of sector OMN = 
= 15.708 square cm
Area of ΔOMN = 2(ΔOPN)
Area of ΔOPN = 
Area of ΔOMN = OP × PN
In ΔOPN,
sin(25°) = 
PN = ONsin(25°)
= 6sin(25°)
= 2.536 cm²
cos(25°) = 
OP = ONcos(25°)
OP = 6cos(25°)
OP = 5.438 cm
Area of ΔOMN = 2.536 × 5.438
= 13.791 cm²
Area of the shaded region = 15.708 - 13.791 = 1.917 cm²
≈ 1.92 cm²
B because I have had this problem and I’m pretty sure it’s b