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stepan [7]
2 years ago
5

What is 1 2/3 - 2 1/3​

Mathematics
1 answer:
victus00 [196]2 years ago
7 0
-2/3 i used my calculator
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−14 − 8x = −2(−3x + 7)
marissa [1.9K]

Answer:

-8x=6x+14-14

-8x-6x=0

-14x=0

X=0/14

X=0

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6 0
3 years ago
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PLEASE HELP
rusak2 [61]
C' ( 4, -2 )

this is the explanation sort of

c ( -2, -3 ), since it is translated six units to the right, add 6 to the x-coordinate and since it is translated one unit up, add 1 to the y-coordinate
7 0
2 years ago
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Write a polynomial function in factored form w zeros at -2,5,6
AlladinOne [14]

Answer:

B

Step-by-step explanation:

The zeros of a polynomial are the solutions to the function. They are found from the factors. The factors which multiply to make the equation in standard form. To write the factors reverse the process by unsolving the factor.

x = -2 comes from x+2

x = 5 comes from x-5

x = 6 comes from x-6

The factored form is (x+2)(x-5)(x-6).

7 0
3 years ago
The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
2 years ago
Angle θ is in standard position. If tan ⁡ θ &lt; 0 and cos ⁡ θ = − 4/5 , find sin ⁡ θ .
Pani-rosa [81]

Answer:

The value found is.

sin θ = 0.6

Step-by-step explanation:

We know that the value of cosθ is given -4/5

cosθ = -4/5

First, lets finds the angle θ by taking inverse of cosine of -4/5

θ = cos⁻¹ (-4/5)

θ = 143.13°

Substitute the found θ = 143.13° it in tanθ to see if satisfies the equation tanθ < 0:

tanθ < 0

tan(143.13°) < 0

-0.75 < 0

Hence the equation is satisfied.

Which means that θ is equals to 143.13° and can be used to find sinθ

sinθ = sin 143.13°

sin 143.13° = 0.6

6 0
3 years ago
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