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2 years ago

What is 1 2/3 - 2 1/3

Mathematics

1 answer:

victus00 [196]2 years ago

7 0

-2/3 i used my calculator

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IQ scores on the WAIS test approximate a normal curve with a mean of 100 and a standard deviation of 15. What IQ score is identi

riadik2000 [5.3K]

Answer:

IQ scores of at least 130.81 are identified with the upper 2%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 100 and a standard deviation of 15.

This means that $\mu = 100, \sigma = 15$

What IQ score is identified with the upper 2%?

IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.

$Z = \frac{X - \mu}{\sigma}$

$2.054 = \frac{X - 100}{15}$

$X - 100 = 15*2.054$

$X = 130.81$

IQ scores of at least 130.81 are identified with the upper 2%.

7 0

3 years ago

Write 25 times 10 to the 6 power in scientific notation

polet [3.4K]

Answer:

2.5*10^7 thank you

Step-by-step explanation:

thank you

3 0

3 years ago

What is the result of converting 60 pounds?

Molodets [167]

Answer:

To kilos? About 132.2. To dollars? Google the exchange.

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3 years ago

Find the slope and reduce of p=(3/4,1 1/4) q=(-1/2,-1)

sergij07 [2.7K]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
p&({{ \frac{3}{4}}}\quad ,&{{ \frac{1}{4}}})\quad 
% (c,d)
q&({{ -\frac{1}{2}}}\quad ,&{{ -1}})
\end{array}$

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-\frac{1}{4}}{-\frac{1}{2}-\frac{3}{4}}\quad \cfrac{\leftarrow LCD=4}{\leftarrow LCD=4}
\\\\\\
\cfrac{\frac{-4-1}{4}}{\frac{-2\cdot 1-3}{4}}\implies \cfrac{\frac{-5}{4}}{\frac{-5}{4}}\implies \cfrac{-5}{4}\cdot \cfrac{4}{-5}\implies 1$

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3 years ago

X 6.4.5-T

butalik [34]

Same strategy as before: transform X ∼ Normal(76.0, 12.5) to Z ∼ Normal(0, 1) via

Z = (X - µ) / σ ↔ X = µ + σ Z

where µ is the mean and σ is the standard deviation of X.

P(X < 79) = P((X - 76.0) / 12.5 < (79 - 76.0) / 12.5)

… = P(Z < 0.24)

… ≈ 0.5948

8 0

3 years ago

What is 1 2/3 - 2 1/3​

What is 1 2/3 - 2 1/3