What is the missing number for n 31.53=62.4?

I can't seem to figure out what numbers to use to solve this equation.

Kazeer [188]

Hello!

The first thing you should notice is that the exponent will be less than 1, as raising 27 to any power greater than 1 will make it larger, and you're trying to figure out what makes it equal to 3, a number less than 27.

Raising a number to a fractional power is taking its nth root: $21^{1/3}$ is $\sqrt[3]{21}$ , so you'll really need to take the nth root of 27 to get 3. To figure out which root, write the number in exponential form with a base of 3:

$27^{x}$ = 3
$3^{3x}$ = $3^{1}$

Now, the bases are the same (they are both 3), so you can set the exponents equal to each other:

3x = 1

Divide both sides by 3 and you've isolated x:

$x = \frac{1}{3}$

Answer:
$27^{1/3} = 3$

6 0

3 years ago

I need help With this plz

s2008m [1.1K]

Answer:

The discount is the same.

Step-by-step explanation:

We need to find the ratios of both discounts.

41/50 = 61.5/75

If the question is True, this means that the ratios should be the same. So we have to cross multiply to find the answer.

75*41 = 50*61.5 = 3075

These two multiplication problems both equal 3075. Since the ratios are equal, the discounts are also equal.

4 0

3 years ago

Math help please..............

hjlf

The answer is 2. The rate of change between -1 and 0 is 3 and between 0 and -1 is 1. The average between 3 and 1 is 2.

6 0

3 years ago

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A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selecti

Andrews [41]

Answer:

(a) Null Hypothesis, $H_0$ : p = 0.50

Alternate Hypothesis, $H_A$ : p > 0.50

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed.

(e) The value of z test statistics is 0.96.

(f) The P-value is 0.1685.

(g) At 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) We conclude that the proportion of baby girls is equal to 0.50.

Step-by-step explanation:

We are given that a 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5.

Assume that sample data consists of 78 girls in 144 births.

Let p = population proportion of baby girls

(a) So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of baby girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the proportion of baby girls is greater than 0.50}

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed as in the alternative hypothesis we are concerned for proportion of baby girls that is greater than 0.50.

(e) The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of baby girls = $\frac{78}{144}$ = 0.54

n = sample of births = 144

So, the test statistics = $\frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{144} } }$

= 0.96

The value of z test statistics is 0.96.

(f) The P-value of the test statistics is given by;

P-value = P(Z > 0.96) = 1 - P(Z < 0.96)

= 1 - 0.8315 = 0.1685

(g) Now, at 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) Since our test statistic is less than the critical value of z as 0.96 < 1.282, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region (which was to the right of value of 1.282) due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of baby girls is equal to 0.50.

7 0

3 years ago

I need to solve this algebra expression

Art [367]

$5-7+2*10$
$5-7+20$
$-2+20=18$
The answer is :18

6 0

3 years ago

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