Let x be the amount (in oz) of pure silver used in this alloy. Each ounce of the pure silver contributes a value of $30.48, so that the total cost of the amount of pure silver that gets used is $30.48x.
The same goes for the secondary alloy, where each ounce costs $21.35, so that 52 ounces of the alloy contributes a total cost of $21.35*52.
The final alloy has a total mass of (x + 52) ounces, and each ounce costs $24.76, so that this alloy's totat cost is $24.76*(x + 52).
So we have
30.48x + 21.35*52 = 24.76*(x + 52)
30.48x + 1110.20 = 24.76x + 1287.52
5.72x = 177.32
=> x = 31
Answer:
12/52 or 23%
Step-by-step explanation:
take the total of all the candy and divide it by the number of green so there are 12 green and 52 over all so it would be 12/52
Answer:
The answer is 2,20
Step-by-step explanation:
i dont know i just quest and go it right
It is called a ray.
segments have two end points. and a ray has one end point ad extends forever in one direction, and a line extends forever in both directions.
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.