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Troyanec [42]
2 years ago
14

Zippy company manufactured 10,000 units in December with a total product cost of $25,472 They had zero finished goods inventory

at the start of December. In December Zippy sold 7,364 units at a unit price of $5.26. Period expenses were $3,722. What is the amount of Zippy's operating income? Round any intermediate calculations to four decimal places.
Mathematics
1 answer:
Mnenie [13.5K]2 years ago
6 0

The amount of Zippy's operating income is

  • $16255.0592

<h3>Cost per unit is given as </h3>

= \frac{total cost of goods manufactured}{number of units}\\\\&#10;= \frac{25472}{10000}\\\\&#10;= $2.5472 per unit&#10;

So, cost of goods sold

= Number of units * cost per unit\\\\&#10;= 7364 * 2.5472 \\\\&#10;= $18757.5808&#10;

Therefore, operating income

= sales - cost of goods sold - period expenses\\\\&#10;= 7364*5.26 - 18757.5808 - 3722\\\\&#10;= $16255.0592&#10;

For more information on operating income, visit

brainly.com/question/16232387

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inna [77]

Answer:

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5 0
3 years ago
If w varies inversely with the square root of t and w = 5 when t = 49,
VARVARA [1.3K]

Answer:

x=k/y

w=k/t

5=k/√49

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k=5×7

k=35

5 0
3 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

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+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

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2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

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+7(−3)

2

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\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

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\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
Is y=3x+4 parallel or perpendicular
Sauron [17]

Answer: y=3x+4 is parallel to y=3x+7

Step-by-step explanation:

<h3> The complete exercise is: "Is y=3x+4 parallel, perpendicular or neither to y=3x+7?"</h3><h3 />

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

First, in order to solve this exercise it is important to remember that, by definition:

1. The slopes of parallel lines are equal.

2. The slopes of perpendicular lines are negative reciprocal.

In this case, you have the following line given in the exercise:

 y=3x+4

You can identify that "m" and "b" are:

m=3\\b=4

And the other line provided in the exercise is this one:

y=3x+7

So, you can identify that:

m=3\\b=7

As you can notice, the slopes of both lines are equal; therefore, you can conclude that those lines are parallel.

6 0
3 years ago
Question 11 (5 points)
Semenov [28]

Hello :)

here you need to use the slope intercept formula to find your equation:

y= mx+b

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your answer would be a) y = -3x - 2

8 0
3 years ago
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