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2 years ago

10

The Kicking Cacti and the Sprinting Stingrays met in their town's annual kickball championship this year. They were so evenly ma

tched that the game lasted 11 innings! The Stingrays had 3 pitchers, and each of them pitched for the same number of innings.
How long did each of the pitchers for the Stingrays pitch?

1 answer:

wolverine [178]2 years ago

3 0

Answer:

11/3 = 3 2/3 innings

Step-by-step explanation:

3 pitchers = 11 innings

1 pitcher = x innings

in the first equation, divide both sides by 3 to get 1 pitcher on one side

1 pitcher = 11/3 innings = 3 2/3 innings

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In health class, students record the weights of the sandwiches they have for lunch. The weights are shown in the line plot below

Dvinal [7]

To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
2/8+6/8 = 1
1 + 1 + 1 =3
now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
therefore, we get 3/10. because this can't be simplified, this will be your final answer.

4 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

3 years ago

16 square meters is equivalent o how many square yards

Marat540 [252]

Answer: 19.13 yd²

Step-by-step explanation:

1. By definition, you have that 1 square meter is equal to 1.19599 square yards. You can express it as following:

1 m²= 1.19599 yd²

2. Then, keeping the information above on mind, you can make the conversion from 16 m² to yd² as it is shown below:

$(16m^2)(\frac{1.19599yd^2}{1m^2})=19.13yd^2$

Therefore, you have that 16 m² is equivalent to 19.13 yd².

6 0

3 years ago

the gravitational attraction between two masses varies inversely as the square of the distance between them. if the attraction f

Marat540 [252]

Answer:

33 1/3 lb

Step-by-step explanation:

When the distance between them goes from 8 ft to 12 ft, it is 1.5 times what it was. Then the force will be multiplied by the inverse of the square of this:

(75 lb)×1/(1.5²) = 75/2.25 lb = 33 1/3 lb

At 12 feet apart, the attraction force is 33 1/3 pounds.

8 0

3 years ago

Find the product. state your answer in standard form <br><br> (x+7)(x squared + 6x - 8)

USPshnik [31]

Answer:

${x}^{3} + 13 {x}^{2} + 34x - 56$

Step-by-step explanation:

$(x + 7)( {x}^{2} + 6x - 8) \\ = x ( {x}^{2} + 6x - 8) + 7( {x}^{2} + 6x - 8) \\ = {x}^{3} + 6 {x}^{2} - 8x + 7 {x}^{2} + 42x - 56 \\ = {x}^{3} + 6 {x}^{2} + 7 {x}^{2} + 42x - 8x - 56 \\ = {x}^{3} + 13 {x}^{2} + 34x - 56 \\$

6 0

3 years ago

Read 2 more answers