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VLD [36.1K]
2 years ago
14

What is the x-intercept of the graph that is shown below?

Mathematics
1 answer:
Lorico [155]2 years ago
7 0

Answer:

(-2, 0)

Step-by-step explanation:

its where the line crosses through the x-axis

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Mrs. DeMarco wants to estimate the height of her garage
valkas [14]

Answer:

length of baseball bat.

Step-by-step explanation:

she can measure the bat and times by how many times she could fit the bat there u know

6 0
3 years ago
You open a small business with an intial investment of $90,000. The weekly running costs for the business are $7800. the weekly
GREYUIT [131]

Answer:

90000=1000x

90 days

Step-by-step explanation:

90000=8800x-7800x

90000=1000x

4 0
2 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
Problems on a Test
patriot [66]
G = 4n is the correct equation to use. Eg 10 x 4 = 40, 18 x 4 = 72 and 21 x 4 = 84
6 0
3 years ago
Write an equation for your trend line?
Soloha48 [4]
Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.

Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8

Then set up the "point-slope form":
y - y0 = m * (x - x0)

You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.

x0 = 1
y0 = 10

Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)

The above equation will work fine for an answer, but let's go a step further and solve for y.

y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
y = -9/8x + 9/8 + 80/8
y = -9/8x + (9 + 80)/8
y = -9/8x + 89/8
4 0
3 years ago
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