S+m+l=28
4s+2m+l=58
6s+5m+4l=135
Eliminate the variable l from the first 2 equations
s+m+l=28
-4s-2m-l=-58
-3s-m=-30
Elminiate the variable l from the last 2 equations
6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97
Now solve for s and m using the 2 equations without l
-3s-m=-30
-10s-3m=-97
9s+3m=90
-10s-3m=-97
-s=-7
s=7
Then plug in s into one of the equations without l
-3(7)-m=-30
-21-m=-30
-m=-9
m=9
Now plus in s and m into one of the original 3 equations
(7)+(9)+l=28
16+l=28
l=12
Final answer:
Small=$7
Medium=$9
Large=$12
I know it only asks for large but I wanted to show you how to find them all for future reference. :)
Answer:
This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.
Step-by-step explanation:
What we are asked here is imply to state how long in terms of distance would be Arielle position after 15 minutes
Now, 55 ft will take her 234 minutes
x ft will take her 15 minutes
x * 234 = 55 * 15
234x = 3825
x = 3825/234
x = 16.35 ft
This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.
Answer: -32
Step-by-step explanation:
35 (t + 29) = −3(3 − t)
Open the brackets
35t+1015= -9+3t
Collect like terms
35t-3t=-9-1015
32t= -1024
Divide both side by 32
32t/32 = -1024/32
t= -32
Answer
0.6
Step-by-step explanation:
here is the working out! Can i get brainliest
Circumference of a circle = 2πr
C = 2π(4)
C = 8π
C = 8 * 3.14 = 25.12
In short, Your Answer would be 25.12
Hope this helps!
