To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
You have to multiply by the complex conjugate so that you can clear the radical from the denominator.
Once you do the multiplication simplify the radical. There's still a common factor in -54, -18, & 75 so divide all those by 3.
Answer:
x less than or equal to 5
i think thats what u wanted