Ashlyn needs to bring a dessert to her dinner party. If the bakery has eight pies to choose from, how many ways can Ashlyn choos

Question

2 years ago

10

e three?

1 answer:

Snowcat [4.5K] · Answer 1 · 2023-05-10T10:58:32+03:00

<u>Ashely have </u><u>56 ways</u><u> to choose from</u>

This question can be solved using a system in mathematics called Permutation and it's in a topic of mathematics called combinatorics.

<h3 /><h3>Permutation</h3>

This is the process of arranging a particular set of data in different ways.

Since Ashely is choosing 3 desserts out of 8 in no specific ways

$P=\frac{n!}{(n-r)!}$

Where n = total number of ways available

r = total numbers that would be selected.

Data given

Let's substitute these values into the equation.

$P=\frac{8!}{(8-3)!3!} \\P=\frac{8*7*6*5*4*3*2*1}{5*4*3*2*1*3*2*1}\\P=56$

From the calculation above, Ashley have 56 ways in which can choose 3 dessert from an 8 choice.

Learn more about permutation here;