From the equation that was gotten, the value of the pecan pies and the cheesecake will be $9 each.
Based on the information given, the equations to solve the question will be:
9p + 8s = 153 ..... i
2p + 6s = 72 ..... ii
Multiply equation i by 2
Multiply equation ii by 9.
18p + 16s = 306
18p + 54s = 648
Subtract the equations
38s = 342
s = 9
Since 2p + 6s = 72
2p + 6(9) = 72
2p + 54 = 72
2p = 72 - 54.
2p = 18
p = 18/2 = 9
They're both $9 each
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The minimum point on the graph of the equation y=f(x-5) is (-6, -3)
<h3>How to determine the minimum?</h3>
The initial minimum is given as:
(-1, -3)
The transformation y = f(x - 5) means that:
(x, y) = (x - 5, y)
So, we have:
(x, y) = (-1 - 5, -3)
Evaluate
(x, y) = (-6, -3)
Hence, the minimum point on the graph of the equation y=f(x-5) is (-6, -3)
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Answer:
x = 20
Step-by-step explanation:
Using the vertical angle theorem, you will find that 7x - 99 = 2x + 1.
7x - 99 = 2x + 1
+99 both sides
7x = 2x + 100
-2x both sides
5x = 100
÷5 both sides
x = 20
The answer is x = 20.
Answer:
A: The solution to this system is no viable because it results in fractional values of tickets
Step-by-step explanation:
Let number of adult, child, and senior tickets be x, y and z respectively.
Thus;
x + y + z = 12 - - - (eq 1)
she purchases 4 more child tickets than senior tickets.
Thus, y = z + 4
Thus:
x + (z + 4) + z = 12
x + 2z + 4 = 12
x + 2z = 8 - - - (eq 2)
Also, We are told that Adult tickets are $5 each, child tickets are $2 each, and senior tickets are $4 each. She spends a total of $38,
Thus;
5x + 2(z + 4) + 4z = 38
5x + 2z + 8 + 4z = 38
5x + 6z + 8 = 38
5x + 6z = 38 - 8
5x + 6z = 30
Divide through by 5 to get;
x + (6/5)z = 6 - - - (eq 3)
Subtract eq 2 from eq 1 to get;
2z - (6/5)z = 8 - 6
2z - (6/5)z = 2
Multiply through by 5 to get;
10z - 6z = 10
4z = 10
z = 2½
It's not possible to have a fractional value of a ticket and thus we can say that the solution is not viable.
