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Svet_ta [14]
2 years ago
7

A cash card has a starting value of $25. If the card is not used within the first year of its purchase, the value on the card be

gins to decrease by $2.50 per month.
The relationship between the number of months after the first year and the amount remaining on the card is .

The independent variable is the _____________?

The dependent variable is the ______________?
Mathematics
1 answer:
Gre4nikov [31]2 years ago
8 0

Answer:

  • The relationship between the number of months after the first year and the amount on the remaining card is linear and inverse ( Which meant that ,when the number of months after the first year increases , the amount on the remaining car decreases , in a linear way ) .

  • The Independent variable is the <u>numbers of months after the first year .</u>

  • The Dependent variable is the<u> </u><u>amount on the remaining card , Bcoz this amount depends on the time it has passed since the first year , ( which is our independent variable!).</u>

  • <u>If </u><u>we </u><u>call </u><u>"</u><u>Y"</u><u> </u><u>our </u><u>dependent</u><u> </u><u>variables</u><u> </u><u>and </u><u>"</u><u>X"</u><u> </u><u>our </u><u>Independent</u><u> </u><u>variable</u><u> </u><u>,</u><u> </u><u>This </u><u>relationship</u><u> </u><u>can </u><u>be </u><u>written</u><u> </u><u>as </u><u>Y=</u><u> </u><u>2</u><u>5</u><u> </u><u>-</u><u> </u><u>2</u><u>.</u><u>5</u><u>x</u><u>.</u>

  • <u>If </u><u>no </u><u>months </u><u>had </u><u>passed </u><u>since </u><u>the </u><u>first</u><u> </u><u>year,</u><u> </u><u>then </u><u>x=</u><u> </u><u>0</u><u> </u><u>and </u><u>the </u><u>amount</u><u> </u><u>in </u><u>the </u><u>card </u><u>equals </u><u>$</u><u>2</u><u>5</u><u> </u><u>,</u><u> </u><u>While </u><u>if </u><u>one </u><u>month </u><u>has </u><u>passed </u><u>since </u><u>the </u><u>first </u><u>year </u><u>x=</u><u> </u><u>1</u><u> </u><u>and </u><u>y=</u><u> </u><u>2</u><u>2</u><u>.</u><u>5</u><u> </u><u>(</u><u> </u><u>The </u><u>amount</u><u> </u><u>in </u><u>the </u><u>card </u><u>in </u><u>this </u><u>case </u><u>is </u><u>$</u><u>2</u><u>2</u><u>.</u><u>5</u><u> </u><u>.</u>

Step-by-step explanation:

<h2>Hope this helps you !! </h2>
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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

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Answer: Option D

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We know that the cost of preschool is $ 45 per day plus a monthly fee of $ 70.

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To write an equation that represents this situation, let us call d the number of days that Barry attends school

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d= 18\ days

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