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tamaranim1 [39]

1 year ago

9

Which of the following is a ballistic stretching exercise?

2 answers:

Vladimir [108]1 year ago

7 0

Answer:

B. Arm circles

Hope you have a great day :)

IrinaVladis [17]1 year ago

5 0

The answer is B - arm circles ….

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A six-sided die is rolled two times. What is the theoretical fractional probability that the first number is even and the second

Nostrana [21]

Answer:

The theoretical probability that the first number is even and the second number is odd is $\frac{1}{4}$ .

Step-by-step explanation:

Since each dice has six sides, and there are two die, the total amount of different outcomes are $6^2$ or 36. The probability of getting an even number on the first roll is $\frac{3}{6}$ or $\frac{1}{2}$ , and the probability of getting an odd number on the second roll is also $\frac{3}{6}$ or $\frac{1}{2}$ , so the probability of getting an even number on the first roll and an odd number on the second roll is $\frac{1}{2} * \frac{1}{2} = \frac{1}{4}$ .

6 0

2 years ago

Aaron wants to make a path to guide guest through the conservation area.He uses rolls of rope to make the path.He uses 3/4 of a

mel-nik [20]

Answer:

Aaron needs <u>2 more rolls</u> to complete the path.

Step-by-step explanation:

Given:

Total rolls Aaron has = 4

Part of path covered by using $\frac{3}{4}$ of a roll = $\frac{1}{8}$

So, in order to find the number of rolls required to cover the complete path is given using the unitary method.

Rolls used for $\frac{1}{8}$ of a path = $\frac{3}{4}$

Therefore, rolls used to cover the whole path is given by dividing the rolls used for one-eighth of the path and the path covered. This gives,

$=\frac{3}{4}\div \frac{1}{8}$

$=\frac{3}{4}\times \frac{8}{1}$

$=\frac{3\times 8}{4\times 1}$

$=\frac{24}{4}$

$=6\ rolls$

Now, rolls required to complete the path is 6. But Aaron has only 4 rolls.

So, he will need 6 - 4 = 2 rolls more to complete the path.

5 0

3 years ago

alexira [117]

True, because the triangle is symmetrical

Hope this helps :)

8 0

3 years ago

Read 2 more answers

If the dimensions of a rectangle are A plus 3b and A minus 3b what is the area of the rectangle

tresset_1 [31]

area=legnth times width

we notice this is a special case

(a+b)(a-b)=a^2-b^2

area=(a+3b)(a-3b)=a^2-9b^2

area=a^2-9b^2

5 0

2 years ago

Graph the linear equation. X = y + 5

Zina [86]

X = y + 5
-y + x - x = y - y + x + 5
-y = x + 5
y = x - 5

6 0

2 years ago