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makkiz [27]
3 years ago
8

Andrew is selling tickets for the school play, and charges t dollars for adult tickets and 2 dollars for child tickets. On Monda

y, he sold 18 child tickets and 5 adult tickets. On Tuesday, he sold 10 child tickets and 9 adult tickets. If Andrew made the same amount of money on both days, find the price for an adult ticket.
Mathematics
1 answer:
Andru [333]3 years ago
3 0

Answer:

T=4 plz make brainlest answer

Step-by-step explanation:

Monday overall cost 36+5t

Tuesday overall cost 20+9t

36+5t=20+9t

-20 -20

16+5t =9t

-5t -5t

16=4t

t=4

Check

36+5t=20+9t (t=4)

36+20=20+36

It works

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Answer:

Step-by-step explanation:5,7 3,9

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The seats at a local baseball stadium are arranged so that each row has five more seats than the row below it. If there are 4 se
nordsb [41]

Givens:

a = 4; n = 23; d = 5

Formula

L = a + (n - 1)*d

Substitute and solve

L = 4 + (23 - 1)*5

L = 4 + 22*5

L = 4 + 110

L = 114 Answer

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3 years ago
I don’t know the answer and I’m not good at math at all
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Answer: Tia payed .15 more

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Paola is selling bags of homemade caramel corn for a club fundraiser. The amount she makes depends on the number of bags sold. B
BlackZzzverrR [31]

Answer:

She realised $12 from selling 8 bags of caramel corn

Step-by-step explanation:

Given

(8, 12)

Required

Determine what it means based on the available information

A function is always written as (x,y)

Where x is dependent on y

By comparison,

x = bags of caramel corn = 8

y = amount realised = 12

Assuming the currency is in dollars

Conclusively,

She realised $12 from selling 8 bags of caramel corn.

5 0
3 years ago
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
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