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2 years ago

Not sure how difficult this would be to solve

Mathematics

1 answer:

mr_godi [17]2 years ago

3 0

F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4

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Answer:

(1.5, -13.5)

Step-by-step explanation:

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Answer:

$y=-3.2\\\\y=-2.2\\\\y=-1.8$

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

$y=0.2x-2$

$x:-6,-1,1$

Insert -6:

$y=0.2(-6)-2$

Simplify multiplication (when multiplying a negative and a positive, the result will always be negative):

$y=-1.2-2$

Simplify (when subtracting from a negative number, add the values, but keep the negative symbol):

$y=-3.2$

Insert -1:

$y=0.2(-1)-2\\\\y=-0.2-2\\\\y=-2.2$

Insert 1:

$y=0.2(1)-2\\\\y=0.2-2\\\\y=-1.8$

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3 years ago

The function g(x)=x^2+3. The f(x)=g(x+2)

vekshin1

Answer:

$f(x)=x^2+6x+12$

Step-by-step explanation:

Given:

The function 'g(x)' is given as:

$g(x)=x^2+3$

Now, the function 'f(x)' is given as:

$f(x)=g(x+2)$

So, the function 'f(x)' is a transformation of 'g(x)'.

In order to find f(x), we replace 'x' by $(x + 2)$ in the 'g(x)' function equation. This gives,

$g(x+2)=(x+2)^2+3$

Using the identity $(a+b)^2=a^2+b^2+2ab$ , we get:

$g(x+2)=x^2+3^2+6x+3\\\\g(x+2)=x^2+9+6x+3\\\\g(x+2)=x^2+6x+12$

Hence the function f(x) is given as:

$f(x)=x^2+6x+12$

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3 years ago

If the mean of the data below is 3.8, find m<br>x 1 2 3 4 5 6<br>f 1 4 7 m 6 3

zloy xaker [14]

Answer:

m = 1.8

Step-by-step explanation:

Given data is as follows :

x 1 2 3 4 5 6

f 1 4 7 m 6 3

We need to find the value of m if the mean of the data is 3.8.

Mean = sum of observations/no. of observations

So,

$3.8=\dfrac{1+4+7+m+6+3}{6}\\\\22.8=21+m\\\\22.8-21=m\\\\m=1.8$

So, the value of m is equal to 1.8.

8 0

3 years ago