Considering it's vertex, the quadratic equation that could be represented on the plane is given as follows:
f(x) = (x - 8)² - 6.
<h3>What is the equation of a parabola given it’s vertex?</h3>
The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
Researching the problem on the internet, it is found that the given graph has vertex at (8,-6), hence <u>h = 8, k = -6 and considering a = 1</u> the equation is given as follows:
f(x) = (x - 8)² - 6.
More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967
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I’m pretty sure the answer is d or c
Answer: 30 students more voted for Gerardo than for Juju.
Explanation:
<u>so 'x' represent the total number of students</u>
<u />
<u>0.40x of the students voted for Gerardo</u>
<u />
<u>0.35x of the students voted for Leandro</u>
<u />
<u>0.25x of the students voted for Juju</u>
<u />
<u>70 students voted for Leandro:</u>
<u />
<u>0.35x = 70 </u>
<u />
<u>by solving we find:</u>
<u />
<u>x = 200 students</u>
<u />
<u>0.40x - 0.25x = (0.40 - 0.25)x = 0.15x = 0.15*200 = 30</u>
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Answer:
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. (In grammar school, you probably called the domain the replacement set and the range the solution set.
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
To find the coordinates of the midpoints, add the x's and divide by 2 and add the y's and divide by 2.
The coordinates of D, the midpoint of AB, (1+3)/2 will be the x-coordinate and (4+0)/2 will be the y-coordinate.
D (2,2)
You could also see this on a graph, see image.
E, the midpoint of AC has the x-coordinate (1+-3)/2, which is -1 and y-coordinate (4+-2)/2 which is 1.
E is (-1,1)
Then we are able to calculate the slope of DE and BC.
To calculate slope, subtract the y's and put that on top of a fraction and subtract x's and put that on the bottom of a fraction. If the slopes are the same the segment are parallel.
Slope of DE:
(2-1)/(2--1)
= 1/3
Slope of BC:
(0--2)/(3--3)
=2/6
=1/3
The slopes of BC and DE are equal, so the segments are parallel.
(Alternatively, you could show that Triangle ABC and Triangle ADE are similar. Then find the segments parallel because corresponding angles are congruent.)
