Change the w-3/w+5 fraction into an equivalent fraction with the denominator w2 + w

Christian purchased a new car. The value of the car is depreciating at a

LenKa [72]

18000 represents the price of the new car.

The value of the car in 6 years can be found by substituting 6 for the variable t, as follows:

$V = 18000(1-.12)^6\\V = 18000(0.4644)\\$

In 6 years, it will be worth around $8359.27.

The equation for the car worth $20000 is this:

$V = 20000(1-.15)^6\\V = 20000(0.3771)\\$

In 6 years, the other car will be worth $7542.99, so the car worth $18000 will have more value in 6 years.

3 0

3 years ago

Need help from the same last question. (I dont need to do #10)

AysviL [449]

8. The y-intercept is -10. You can find this by just seeing where the line would hit the y-axis. This is basically the starting point so the Scuba Diver's decent started at -10m.

9. You have the y-intercept so put that in slope-intercept form. y=mx+b

y=mx - 10

Now find the slope by picking two points and using the slope formula. I'll use
(30,-6) and (50,-4), and then plug in the values. 30 = x1, -6 = x2, 50 = x2, -4 = -4. Simplify.

m= y2-y1 -4 - (-6) 2 1
-------- = ----------- = --- / 2 = ---
x2-x1 50 - 30 20 10

8 0

3 years ago

What is the slope of the line QR?

svetoff [14.1K]

Answer:

-3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the product of 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°))

saveliy_v [14]

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is 520[cos(18) + isin(18)]

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Complex number is in the form z = a + bi, where a and b are real numbers.

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is:

z = 65 * 8 [cos(14 + 4) + isin(14 + 4)] = 520[cos(18) + isin(18)]

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

2 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Change the w-3/w+5 fraction into an equivalent fraction with the denominator w2 + w – 20