3 years ago

Change the w-3/w+5 fraction into an equivalent fraction with the denominator w2 + w – 20

1 answer:

svp [43]3 years ago

7 0

$\dfrac{w-3}{w+5}=\dfrac{(w-3)(w-4)}{(w+5)(w-4)}=\dfrac{w^2-4w-3w+12}{w^2+5w-4w-20}=\dfrac{w^2-7w+12}{w^2+w-20}$

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