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strojnjashka [21]
3 years ago
12

Change the w-3/w+5 fraction into an equivalent fraction with the denominator w2 + w – 20

Mathematics
1 answer:
svp [43]3 years ago
7 0
\dfrac{w-3}{w+5}=\dfrac{(w-3)(w-4)}{(w+5)(w-4)}=\dfrac{w^2-4w-3w+12}{w^2+5w-4w-20}=\dfrac{w^2-7w+12}{w^2+w-20}
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Select all the examples of categorical data. colors number of siblings favorite pet profits genre of music
bulgar [2K]

Answer:

Color, favorite pet, genre of music

Step-by-step explanation:

Categorical variables are simply statistical variables which are non - numeric, usually employed in characterization and groupings based on a certain number of fixed attributes, categories. In the options atated above, the categorical variables fall under a heading with a limited and fixed attributes such as color, pet and genre of music. However, options such as number of siblings and profit are purely numeric variables which can take up any numeric digits and allow for direct numeric computation. They are called quantitative variables.

3 0
3 years ago
72 times what gives you 6834
Lorico [155]

Answer:

94.917

Step-by-step explanation:

6834/72 = 94.916666

7 0
3 years ago
A small cottage is 24 feet long by 40 feet wide the owners plan to double the width and increase the length of the cottage by 20
Alla [95]

Answer: The new cottage will be 2,560 square feet larger than the small cottage.

Step-by-step explanation:

4 0
1 year ago
Which values are outliers?
SSSSS [86.1K]
Answer:
0.8 Not Outlier
1.1 Not Outlier
10.2 Not Outlier
10.9 Not Outlier 

Solution:
Arranging the numbers in ascending order:
     0.8   1.1   4.9   5.2   5.8   5.9   6.1   6.1   7.4   10.2   10.9
we can see that the median is 5.9.

We can find the first quartile Q1 by getting the median in the lower half of the data 
     0.8   1.1   4.9   5.2   5.8
that is, Q1 = 4.9

We can find the third quartile Q3 by getting the median for the upper half of the data 
     6.1   6.1   7.4   10.2   10.9
that is, Q3 = 7.4

We subtract Q1 from Q3 to find the interquartile range IQR.
     IQR = Q3 - Q1 = 7.4 - 4.9 = 2.5

We can now calculate for the upper and lower limits:
     upper limit = Q3 + 1.5*IQR = 7.4 + (1.5*2.5) = 11.15
     lower limit = Q1 – 1.5*IQR = 0.8 - (1.5*2.5) = -2.95
There is no data point that lies above the upper limit and below the lower limit, therefore, there are no outliers in the data set.
8 0
3 years ago
Read 2 more answers
HELPPP MEEEE ASAPPPP Identify the constant of proportionality in the equation below
Umnica [9.8K]

Answer:

it's 3

I am typing this to get over the 20 character limit

5 0
3 years ago
Read 2 more answers
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