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Westkost [7]
3 years ago
6

PLZ HELP HURRY??!!!​

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0
Y=5x+2 let me know if I’m right
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Graph and find the x-intercept, y-intercept, domain, range, and horizontal asymptote of the function y = 4x
adell [148]

The function y=4x is a line. As such, its domain and range is the whole real number set \mathbb{R}, and it has no horizontal nor vertical asymptotes.

Moreover, there's no constant term, so it's x and y intercept is the origin (0,0).

3 0
4 years ago
A lil help , What is g(h(10))?
PIT_PIT [208]

Answer:

2√2

Step-by-step explanation:

Given

g(x) = ✓(x - 4)

h(x) = 2x - 8

Now

g(h(10))

= g ( 2 * 10 - 8)

= g(20-8)

= g(12)

=✓(12 - 4)

= ✓8

=2√2

Hope it will help ✓

6 0
3 years ago
A closed form for the sum $$ s = \frac {2}{3+1} + \frac {2^2}{3^2+1} + \cdots + \frac {2^{n+1}}{3^{2^n}+1} $$ is $1 - \frac{a^{n
miskamm [114]
Can you write the question again?
3 0
4 years ago
What is the distance from the right center field fence to third base? Show all of your work and round
Karolina [17]

Answer:

381.5\,\,\,ft

Step-by-step explanation:

Given:  Figure

To find: distance from the right center field fence to third base

Solution:

In a right angled triangle,

using Pythagoras theorem, square of hypotenuse is equal to sum of squares of base and perpendicular.

In ΔBAC,

BC^2=AB^2+AC^2\\(392)^2=x^2+(90)^2\\153664=x^2+8100\\153664-8100=x^2\\145564=x^2\\\sqrt{145564}=x\\381.5\,\,\,ft=x

So,

distance from the right center field fence to third base is 381.5 foot.

8 0
3 years ago
PLEASEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEE
spayn [35]

Answer:

First, find the multiplier  ( 100-18/100)

=0.82

364000*0.82

=298480 is the new value after the years

7 0
3 years ago
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