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Mashutka [201]
3 years ago
15

What can you multiply to get 60.90

Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0

<em>We can multiply 2 by 30.45 in order to get 60.90</em>

<h2>Explanation:</h2>

Suppose you have two numbers x and y. We can write an equation such that:

xy=60.9

For this equation we have infinitely many solutions. Let's say x equals 2 in this case, so we can isolate y in order to solve this problem:

xy=60.90 \\ \\ If \ x=2 \\ \\ 2y=60.90 \\ \\ y=\frac{60.90}{2} \\ \\ y=30.45

So <em>we can multiply 2 by 30.45 in order to get 60.90</em>

<h2>Learn more:</h2>

Identity property of multiplication: brainly.com/question/4677597

#LearnWithBrainly

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Studentka2010 [4]

Part A: Vertical asymptote is x=0

Part B: Domain is \left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)

Part C: Horizontal asymptote is y=4

Part D: Range is \left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

Explanation:

Part A: We need to determine the vertical asymptote

The vertical asymptote of a function can be determined by equating the denominator equal to zero.

Thus, we have,

x=0

Hence, the vertical asymptote is x=0

Part B: We need to determine the domain

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Let us take the denominator and equate to zero.

Hence, we have, x=0

Therefore, the function is undefined at the point x=0

Thus, the domain of the function is \left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)

Part C: We need to determine the horizontal asymptote

The horizontal asymptote of the function can be determined by dividing the leading coefficient of the numerator by leading coefficient of the denominator.

Thus, we have, y=4

Hence, the horizontal asymptote of the function is y=4

Part D: We need to determine the range

The range of the function is the set of all dependent y -values of the function.

In other words, the range of the function can be determined by substituting the values for x.

Thus, we have,

\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

Therefore, the range of the function is \left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)

6 0
3 years ago
Which rule describes the transformation? picture below​
goldenfox [79]

Answer:

B) rotation 180 degrees about the origin

Step-by-step explanation:

Also, what do the words underneath D) say? I think the answer could also be a reflection across y = x.

7 0
3 years ago
A random sample of 600 adults is taken from a population of over one million, in order to compute a confidence interval for a pr
Maksim231197 [3]

Answer:

9994000

Step-by-step explanation:

4 0
3 years ago
Is 2.799 greater than 2.79 ?
BlackZzzverrR [31]
Yes because 2.799 has a extra digit but if there is an answer that they can be the same then they are the same
6 0
4 years ago
Find the surface area of the present.<br><br> square : 15cm width and 15cm length
VladimirAG [237]

Answer:

The area of the square is 225 cm².

Step-by-step explanation:

Since the geometric figure has a shape of a square, which is a special form of rectangle that has all the sides with the same length, then it's surface area is given by the following formula:

area = length*width = length^2

We can solve for the area by applying the data from the problem, we have:

area = (15)^2

area = 225 cm^2

The area of the square is 225 cm^2.

6 0
3 years ago
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