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kherson [118]
3 years ago
5

there are 320 seniors at strong field high school. if 90% of them go expect to go to college, how many of the seniors expect to

go to college?
Mathematics
2 answers:
weqwewe [10]3 years ago
8 0
288. to figure this out I set up a proporton, 90 (percent) over 100 ( percentages are always out of 100) and x ( the variable, what's ere trying to figure out) over 320 (since we are trying to find what over 320 is equal to 90 out of 100.
\frac{90}{100}  =  \frac{x}{320}
after cross multiplying, you find that 90/100 is equal to 288/320
deff fn [24]3 years ago
7 0

\bf a\%~of~b \implies \cfrac{ a}{100}\cdot b~\hfill
\textit{90\% of 320 is }\cfrac{90}{100}\cdot 320

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Which statement is NOT always true?
BartSMP [9]
B. The product of two irrational numbers if rational

Example: The square root of 2 times the square root of 3, is the square root of 6, which is still irrational. 
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3 years ago
Which is the product of 4^4(4^-7)(4)?
Degger [83]

Answer:

1/16 or 0.0625

Step-by-step explanation:

we can take 4 outside the parentheses and we would get 4^(4-7+1)=4^(-2)= 1/(4^2)=1/16=0.0625.

3 0
3 years ago
Read 2 more answers
Which point would be a solution to the system of linear inequalities shown below? y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1 y&g
Sauron [17]

Answer:

x < \frac{20}{17} and y \ge \frac{-5}{17}

Step-by-step explanation:

Given

y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1

Required

Find x and y

In the second equation. Assume that:

y = \frac{3}{5}x - 1\\

Substitute y = \frac{3}{5}x - 1 in the first equation

y > 4x - 5

\frac{3}{5}x - 1 > 4x - 5

Collect like terms

\frac{3}{5}x - 4x >  - 5 + 1

\frac{3}{5}x - 4x >  -4

Multiply through by 5

3x - 20x > -20

-17x > -20

Solve for x

x < \frac{20}{17}

Substitute this value of x in y \ge \frac{3}{5}x - 1

y \ge \frac{3}{5}*\frac{20}{17} - 1

y \ge \frac{3}{1}*\frac{4}{17} - 1

y \ge \frac{12}{17} - 1

y \ge \frac{12- 17}{17}

y \ge \frac{-5}{17}

3 0
3 years ago
3x² + 2x + 2 + 4x² + 5 Simplify​
Natalka [10]

Answer: 7x^2 + 2x + 7

Step-by-step explanation:

Combine likes terms that have alike variables and alike exponents.

(3x^2 + 4x^2) + (2x) + (2 + 5)

7x^2 + 2x + 7

6 0
3 years ago
15 points and crown <br> solve by factoring (x+6)(2x-5)=0<br> I am confused
Reika [66]
Remember, in order for this equation to be true either one of the polynomials has to equal 0
So:

-> x+6 = 0

x=-6


-> 2x-5 = 0

2x= 5

x= 5/2


So the answer is x=-6 and x= 5/2.


Hope this helps!
7 0
3 years ago
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