This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
−3x + 6 = 5 | -6 (first step is: "subtract 6 from both sides" <span>)
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-3x = 5-6
-3x = -1 | /(-3) (second step is: "<span>divide by (-3) on both sides</span>" <span>)
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9xh = total cost of the hat
9 per hat - 4 = $5 each scarf
h = hat
s = scarf
(9xh) + (5x s)
(9x7) + (5x9) = 108
Point v is graphed on a number line at -6...point u is 8 units away from v....notice that it doesn't say which way....so it can go either way....so we need to find 8 units away from -6 in both directions
-6 + 8 = 2
-6 - 8 = -14
so point u can be either at 2 or at -14...ur answers are A and D