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Anettt [7]
2 years ago
8

A set of 3 consecutive integers has a sum of 15. Which integers are they?

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
5 0

The answer is 4+5+6=15.Hope that helps. :)

Elodia [21]2 years ago
3 0

Answer:

Step-by-step explanation:

Let the first number be x,

The second number (since it is consecutive) will be = x + 1

The third number (since it is right after the second) = (x+1) + 1 = x + 2

x + x + 1 + x + 2 = 15

3x + 3 = 15

3x = 15 - 3

3x = 12

x = 12/3 = 4

If the first number = 4,

Second number will be = 5 [(x+1) = 4+1]

Third number will be = 6 [(x+2) = 4 + 2]

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Eddi Din [679]
Simple,

writing out the problem...

\frac{10-4x(6+5-1)}{15}

Simplify it...

-4x(6+5-1)

-4x(11-1)

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Making it look like...

\frac{10-40x}{15}

Cancel out the common factors...

Thus making the answer:

- \frac{2(4x-1)}{3}.

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SashulF [63]

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3 years ago
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Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

<u>Solution:</u>

We have been given two equations which are as follows:

3x - 4y = -24   ----- eqn 1

x + 4y = 8   -------- eqn 2              

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

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Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

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Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

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Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

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