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2 years ago

A set of 3 consecutive integers has a sum of 15. Which integers are they?

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

5 0

The answer is 4+5+6=15.Hope that helps. :)

Elodia [21]2 years ago

3 0

Answer:

Step-by-step explanation:

Let the first number be x,

The second number (since it is consecutive) will be = x + 1

The third number (since it is right after the second) = (x+1) + 1 = x + 2

x + x + 1 + x + 2 = 15

3x + 3 = 15

3x = 15 - 3

3x = 12

x = 12/3 = 4

If the first number = 4,

Second number will be = 5 [(x+1) = 4+1]

Third number will be = 6 [(x+2) = 4 + 2]

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Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave

natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\$

So,

$AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units$

The perimeter of triangle will be:

$P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units$

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

#LearnwithBrainly

7 0

3 years ago

Review the steps of the proof of the identity

astraxan [27]

Answer:

step 2

and then step 3 : the error neutralized the error of step 2

Step-by-step explanation:

sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

and because

sin(-b) = -sin(b)

cos(-b) = cos(b)

we have

sin(a - b) = sin(a)cos(-b) + cos(a)sin(-b) =

= sin(a)cos(b) - cos(a)sin(b)

3pi/2 = 270° or -90°.

sin(3pi/2) = sin(270) = sin(-90) = -1

that means, it is the full radius straight down from the center of the circle.

cos(3pi/2) = cos(270) = cos(-90) = cos(90) = 0

so, step 1 is correct :

sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2) =

= sin(A)×0 - cos(A)×(-1) (correct step 2)

but as we see, the provided step 2 is incorrect.

it should have been the indicated

sin(A)×0 - cos(A)×(-1)

and NOT the provided

sin(A)×0 + cos(A)×(-1)

step 3 based on the erroneous step 2 should then have been

sin(A)×0 - (1)cos(A)

but instead another error with the sign was made that neutralized the error of step 2 and we got after this second mistake by pure chance the overall correct step 3

sin(A)×0 + (1)cos(A)

so, again, the first error was made in step 2.

but technically, there was also a consecutive error made in step 3 to bring everything back to the correct approach.

4 0

2 years ago

Tim says that every time you mutiply two

Sunny_sXe [5.5K]

Answer:

I disagree

Step-by-step explanation:

This is not true because when you multiply a number by one. It will give you its number. It may be a larger number than 1 but it is not bigger than both numbers. Also if you multiply 0 by a number. It will eventually give you the answer 0 .It will be smaller than the number you started with. eg 100x0 = 0

4 0

2 years ago

Katie babysits for her neighbor and charges a certain amount per hour. She also charges 1.5 times as much for any hours after 8p

Anon25 [30]

4 p.m to 8 p.m is 4 hrs.....so she worked 4 regular hrs
8 p.m. to 1 a.m is 5 hrs...she she worked 5 hrs for 1.5 times as much

4x + 5(1.5x) = 92
4x + 7.5x = 92
11.5x = 92
x = 92 / 11.5
x = 8 <==== so she charged $ 8 per hr from 4 pm. to 8 pm. and (8 * 1.5) = $ 12 per hr for hrs after 8 p.m

8 0

3 years ago

Consider the initial value problem y′+5y=⎧⎩⎨⎪⎪0110 if 0≤t<3 if 3≤t<5 if 5≤t<[infinity],y(0)=4. y′+5y={0 if 0≤t<311 i

rosijanka [135]

It looks like the ODE is

$y'+5y=\begin{cases}0&\text{for }0\le t$