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ch4aika [34]
2 years ago
11

Can someone help me do this and show work​

Mathematics
1 answer:
bixtya [17]2 years ago
7 0

Answer:

Bank A: 24 years, Bank B: 28 years

Step-by-step explanation:

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The answer to the question is 1 and 3/4
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Which question is being asked in this story problem?
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If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
In art class,Kerion is coloring a pattern where half of the squares on her paper are being colored blue. Of the blue squares,1/3
kolbaska11 [484]
100% of Kerion's paper squares are:
 (100% / 100%) = 1
 Half of the squares of your paper are colored blue:
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 Of the blue squares, 1/3 of them will also have stripes:
 (1/2) * (1/3) = 1/6
 answer
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7 0
3 years ago
A total of 150 students have taken an Algebra 2 final exam. The scores are normally distributed with a mean of 71% and standard
WARRIOR [948]

Answer:

102 students

Step-by-step explanation:

Note that 65% and 71% are both 1 standard deviation from the mean (71%).  According to the empirical rule, 68% of scores lie within 1 std. dev. of the mean.

68% of 150 students would be 0.68(150 students) = 102 students

3 0
3 years ago
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