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Sholpan [36]
4 years ago
15

If 30 percent of a certain number is 240 what is 50 percent the number

Mathematics
2 answers:
Ber [7]4 years ago
4 0

Answer:

400

Step-by-step explanation:

0.30 * x = 240

x = 240/0.30 = 800

0.50 * 800 = 400

Natalija [7]4 years ago
4 0

Answer:

The value of 50 % of number is 400  .

Step-by-step explanation:

Given as :

Let The number be x

According to statement

30 percent of a number is 240

I.e 30 % of x = 240

Or, \frac{30}{100} × x = 240

Or, 0.3 × x = 240

So.  x = \frac{240}{0.3}

∴     x = 800

SO, The number is 800 .

Now again 50 percent of that number = y

I.e y = 50 % of x

or, y =  50 % of 800

Or, y =  \frac{50}{100} × 800

Or, y = 0.5 × 800

∴    y = 400

Hence The value of 50 % of number is 400  . Answer

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54

Step-by-step explanation:

162/3 = 54

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How many different collections can be composed out of 5 red balls 3 white balls and 1 black ball?
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Different collections in total? Or like pairs of 2 how many?
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Evaluate the expression when y = 4. 5 + y + 8<br><br><br> a.13<br> b.17<br> c.21<br> d.72
V125BC [204]

Answer:

17 is the simplified answer.

Step-by-step answer:

Given that:

y = 4.

We have to evaluate:

=5 + y + 8

By putting value of y that is y =4 in above equation:

=5 +4 +8

=9 +8

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So 17 is simplified answer for this question.

I hope it will help you!

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Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter
Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = x coins

So we can have two inequalities.

1) Total number of coins

x+17\geq28\\  [Since minimum number of coins=28]

2) Total value of coins

10x+(25)(17)\leq505 [As 1 dime=10 cents and 1 quarter=25 cents]

10x+425\leq505

Solving inequality (1)

Subtracting both sides by 17.

x+17-17\geq28-17

∴ x\geq 11

Solving inequality (2)

Subtracting both sides by 425.

10x+425-425\leq505-425

10x\leq 80

Dividing both sides by 10.

\frac{10x}{10}\leq \frac{80}{10}

∴ x\leq 8

On combining both solutions

x\geq 11 and  x\leq 8 ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

7 0
3 years ago
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