It would be D because it it based off of knowledge and you are proposing a hypothesis before conducting an experiment to predict what will happen
Answer:
Gastrulation.
Explanation:
Zygote is formed by the fusion of the male and female gamete. The zygote undergoes the process of cleavage to form the different embryonic stages of the offspring.
Gastrulation is the important process of the pre embryonic development. The blastula get multiply and rearranged to form the gastrula. The gsatrulation process includes the formation of three germ layers also known as triploblastic embryo. The three germ layers are ectoderm, endoderm and mesoderm.
Thus, the correct answer is option (C).
Answer:
Statement C is the only one that is necessarily true for exons 2 and 3. It is also true for exons 7 and 8. While statements A and B could be true, they don’thave to be. Because the protein sequence is the same in segments of the mRNA that correspond to exons 1 and 10, neither choice of alternative exons (2 versus 3, or 7 versus 8) can alter the reading frame. To maintain the normal reading frame—whatever that is—the alternative exons must have a number of nucleotides that when divided by 3 (the number of nucleotides in a codon) give the same remainder. Since the sequence of the a-tropomyosin gene is known, it is possible to check to see the actual state of affairs. Exons 2 and 3 both contain the same number of nucleotides, 126, which is divisible by 3 with no remainder.
The answer is C. Alleles form your genetic makup :)
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