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poizon [28]
3 years ago
11

A yogurt company charges 72 cents for a 6 ounces container of yogurt. How much does it charge for an 8 ounce container?

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer:

Step-by-step explanation:

If

72 cents ---> 6 ounces

Xcents  -----> 8 ounces

then

X = [(72)*(8)] / 6

X = 96 cents

Best regards

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An ice cream factory makes 120 quarts of ice cream in 2 hours. How many quarts could be made in 36 hours?
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A 2001 study by two researchers investigated an anti-poverty initiative in Venezuela called POVERTA. POVERTA gave money to poor
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Answer:

1. This is a "RANDOMIZED CONTROLLED EXPERIMENT".

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2. The research has a treatment group and a controlled group.

A treatment group are those group that received some special treatment from the researcher, it can also be called the experimental group. According to the research, the treatment group are those who are in the POVERTA scheme. That is the 320 communities.

A controlled group are those group that were not given any special treatment, but are , separated and studied. According to the research the controlled group are those 185 communities

3. This research provides evidence that being in a community receiving POVERTA benefits is associated with a lower rate of childhood illness. Because after two years, it was noticed the children in the community that receives POVERTA has low rate of illness, than the children in a community that doesn't receive the benefits of POVERTA.

4. This study does not provide evidence that being in a community receiving POVERTA benefits causes a lower rate of childhood illness. Because the research did not involve treatment of illnesses and they is no experimental evidence that shows that POVERTA benefits is interrelated with illness, as illness involves the internal functions of human body.

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3 years ago
For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
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To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

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The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

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Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

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Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

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Answer is <span>C. 80

hope that helps

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