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Factor Completely: 12x2 − 44x + 24 A) 2(2x − 6)(3x − 2) B) 4(x − 3)(3x − 2) C) 6(x − 4)(2x − 1) D) 12(x − 1)(x − 2)
1 answer:
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For this case we have the following functions:
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2