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3 years ago

If DE≅EF, CD = v + 45, and CF = 4v, what is the value of v?

Mathematics

1 answer:

irinina [24]3 years ago

3 0

Answer:

<h2>since DE≅EF</h2>

CD=CF (cpct)

$v + 45 = 4v \\ 4v - v = 45 \\ 3v = 45 \\ v = \frac{45}{3} \\ v = 15$

<h2>hope it helps you<3</h2>

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