4 years ago

Solve the quadratic equation: -x^2 = 4

Mathematics

1 answer:

arsen [322]4 years ago

6 0

So listen to your teacher next time

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$\text{The principal square root}:\\\\\sqrt{a}=b\iff a^2=b\ \text{for}\ a\geq0\ \text{and}\ b\geq0.\\\\\text{The square root:}\\\\\sqrt{a}=b\iff b^2=a\ \text{for}\ a\geq0\\===================$

$\text{If you want the principal square root (arithmetic square root):}\\\\\sqrt{225}=15\ \text{because}\ 15^2=225\\\\\text{If you want square root (algebraic square root):}\\\\\sqrt{225}=\pm15\ \text{because}\ (-15)^2=225\ \text{and}\ 15^2=225$

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