4 years ago

Solve the quadratic equation: -x^2 = 4

Mathematics

1 answer:

arsen [322]4 years ago

6 0

So listen to your teacher next time

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Myrtle took out a 3-year loan for 2050$ at a computer retailer to be paid back with monthly payments at 12% apr compounded month

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Answer:

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Step-by-step explanation:

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4 years ago

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Write an absolute value function that shifted 2 units right. HELPPPP

iVinArrow [24]

Answer: (a)

Step-by-step explanation:

Suppose the original function is $y=\left | x \right |$

To shift it 2 units right, replace x by x-2 such that

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3 years ago

Word form for 6,392,094,003

Burka [1]

Six billion, three hundred ninety-two million, ninety-four thousand and three.

( If it's wrong, please comment about it. )

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3 years ago

What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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3 years ago

Given a large sample of families with three children, what percent of the families will have all boys?

Tamiku [17]

12.5 % or one eighth

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3 years ago