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inessss [21]
2 years ago
15

Evaluate the following and simplify if possible​

Mathematics
1 answer:
Rufina [12.5K]2 years ago
7 0

Refer to the attachment!!

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Write the equation of the line that goes through (2, 1) and is PARALLEL to 4x - 2y = 3 pls help asap! i have more questions like
allsm [11]

Answer:

Step-by-step explanation:

4x-2y=3

Get into y=mx+b

-4x on each side

Then divide by -2

y=2x- 1.5

Now if a line is parallel to another line the slope will be the same. If perpendicular the slope will be the negative reciprocal. As you said it is parallel the slope is 2.

y = mx+b

y = (slope)x + y-intercept

y= 2x + 1

Sorry if it is wrong but I hope it is right

4 0
3 years ago
Please help im almost done​
irga5000 [103]

Answer:

1/4

Step-by-step explanation:

the numerator is 12 because there are 12 possible outcomes.  The numerator is 3 because there are 3 numbers in this set that are greater than 9.  You get 3/12 which then simplifies to 1/4

8 0
3 years ago
At what point does the curve have maximum curvature? y = 9 ln(x) (x, y) =
Andrews [41]

y = 9ln(x) 
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2

curvature k = |y''| / (1 + (y')^2)^(3/2) 

<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2) 
= (9/x^2) / (1 + 81/x^2)^(3/2) 
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)] 
= 9x(x^2 + 81)^(-3/2). 

To maximize the curvature, </span>

we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2) 
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2] 
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2) 

Setting k' = 0 yields x = ±9/√2. 

Since k' < 0 for x < -9/√2 and k' > 0 for x > -9/√2 (and less than 9/√2), 
we have a minimum at x = -9/√2. 

Since k' > 0 for x < 9/√2 (and greater than 9/√2) and k' < 0 for x > 9/√2, 
we have a maximum at x = 9/√2. </span>

x=9/√2=6.36

<span>y=9 ln(x)=9ln(6.36)=16.66</span>  

the answer is
(x,y)=(6.36,16.66)
7 0
4 years ago
COSINE LAW: Solve triangle PQR. round angles to the nearest tenth​
Valentin [98]

Answer:

Hi,

Step-by-step explanation:

PR²=PQ²+QR²-2*PQ*QR*cos(51°)

=15²+12²-2*15*12*cos(51°)

=142,444659....

PR=11.9350...

PQ²=QR²+PR²-2*QR*PR*cos(R)

cos(R)=(12²+142.444...-15²)/(2*12*11.9350...)=0,21451112....

angle R=77,61315...°≈77.6°

angle P=180°-51°-77.6°≈51,4°

4 0
2 years ago
Get Ready, Set
postnew [5]
Wait is this a anime? Can you tell what anime is please?
3 0
3 years ago
Read 2 more answers
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