Hello :
all n in N ; n(n+1)(n+2) = 3a a in N or : <span>≡ 0 (mod 3)
1 ) n </span><span>≡ 0 ( mod 3)...(1)
n+1 </span>≡ 1 ( mod 3)...(2)
n+2 ≡ 2 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 0×1×2 ( mod 3) : ≡ 0 (mod 3)
2) n ≡ 1 ( mod 3)...(1)
n+1 ≡ 2 ( mod 3)...(2)
n+2 ≡ 3 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 1×2 × 3 ( mod 3) : ≡ 0 (mod 3) , 6≡ 0 (mod)
3) n ≡ 2 ( mod 3)...(1)
n+1 ≡ 3 ( mod 3)...(2)
n+2 ≡ 4 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 2×3 × 4 ( mod 3) : ≡ 0 (mod 3) , 24≡ 0 (mod3)
Average rate = distance / time
distance = average rate x time
Range of distance = 2.2(1) to 2.2(3) = 2.2 to 6.6
Required range is all real numbers from 2.2 to 6.6, inclusive.
The percentage of 4c in the expression 0.2c is 2000%
<h3>How to determine the percentage of 4c?</h3>
The expression is given as:
0.2c
The percentage of 4c is then calculated as:
4c/0.2c
Evaluate the quotient
20
Express as percentage
2000%
Hence, the percentage of 4c in 0.2c is 2000%
Read more about percentages at:
brainly.com/question/843074
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Calculater I'm pretty sure
$14.60 would be your answer