Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
Answer:
11/2
Step-by-step explanation:
The semi-major axis is 1/2 of the major axis, a, so a = 11/2.
This graph shifted down 4 units would be y = x^2 - 2.
Different shifts in standard graphs each have to be done in their own way. Shifting up and down is done by manipulating the y-intercept, which is the number at the end of the equation. Since we started at +2 and it is going down 4, it brings us to -2.
Answer:
DOMAIN - 20
RANGE - 10
Step-by-step explanation:
Answer:
6. A= 5^2 B= 7^4 C=2^3 D=9^5
7. A= i dont know B= i dont know C=5*5*5 D=i dont know
Step-by-step explanation:
