Exercise #4: Each of the following fractions can be converted to a whole number using division.

Solve the system by substitution. y = 8x + 32 Y= -8x

leonid [27]

The answer is (x,y) = (-2, 16)

do you need an explanation as well?

6 0

2 years ago

Don’t mind the already answered questions, I need to know the answer for the table, please.

Angelina_Jolie [31]

What does the rest of the question say??

4 0

3 years ago

Which of the following is true about an isosceles trapezoid?

mixas84 [53]

<span>The diagonals are congruent.

</span>

6 0

3 years ago

A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of

Elis [28]

Answer:

$z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933$

$p_v =P(Z$

If we compare the p value obtained and the significance level given $\alpha=0.02$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

$\hat p=0.27$ estimated proportion of arrests that were not prosecuted

$p_o=0.31$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:

Null hypothesis: $p\geq 0.31$

Alternative hypothesis: $p < 0.31$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

If we compare the p value obtained and the significance level given $\alpha=0.02$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.

3 0

3 years ago

Black Diamond Ski Resort charges $50 for ski rental and $15 an hour to ski. Bunny Hill Ski Resort charges $75 for ski rental and

andrew11 [14]

Answer:

The cost of 5 hours of skiing would be the same ($125) after 5 hours.

Step-by-step explanation:

Black Diamond: ChargeBD(h) = $50 + ($15/hr)h, where h is the number of hours spent skiing.

Bunny Hill: ChargeBH(h) = $75 + ($10/hr)h

We equate these two formulas to determine when the cost of using the ski slopes is the same:

ChargeBD(h) = $50 + ($15/hr)h = ChargeBH(h) = $75 + ($10/hr)h

We must now solve for h, the number of hours spent skiing:

50 + 15h = 75 + 10h

Grouping like terms, we obtain:

5h = 25, and so h = 5 hours.

The cost of 5 hours of skiing would be the same ($125) after 5 hours.

3 0

3 years ago