The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:
x = -3, y = 2
The given system of equations:
x + 2y = 1............(1)
-3x - 2y = 5..........(2)
This can be written in matrix form as shown:
Find the determinant of
The solution to the system of equations x + 2y = 1 and -3x-2y = 5 is:
x = -3, y = 2
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+
= 34
The equation of a circle in standard form is
+
=
where (a , b) are the coordinates of the centre and r is the radius
The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints
Using the midpoint formula
midpoint = [(x
+
,
(
+
where (,
=(3,8) and (
,
=(-7,2)
centre = ((3-7),
(8+2)) = (-2,5)
Calculate r using the distance formula
r = √(-
)²+(
-
)²)
= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34
equation of circle is : (x+2)²+(y-5)² = 34