Answer:
Vertex (-2.5,-300)
Step-by-step explanation:
We are given with h(t)=-16 t^2 +80 t. We are asked to find the vertex.
X-coordinate of vertex =
Where 'a' is coefficient of term
'b' is coefficient of 't' term.
From given function, a= -16
b=80
So,
x-coordinate of vertex =
=-2.5
y-coordinate of vertex =
Simplify it,
=-100 -200
= -300
So, vertex is at (-2.5, -300).
Answer:
Step 3 they took the square root incorrectly
Step-by-step explanation:
5 ( x-2)^2 +6 = 86
Subtract 6 from each side
5 ( x-2)^2 +6 -6= 86-6
5 ( x-2)^2 = 80
Divide each side by 5
5 ( x-2)^2 /5 = 80/5
(x-2)^2 = 16
Take the square root of each side
sqrt((x-2)^2) = ±sqrt(16)
x-2 = ±4
Answer:
-4 =x
Step-by-step explanation:
2x - 5= 5x + 7
Subtract 2x from each side
2x-2x - 5= 5x-2x + 7
-5 = 3x+7
Subtract 7 from each side
-5-7 = 3x+7-7
-12 = 3x
Divide by 3
-12/3 = 3x/3
-4 =x
Answer:
= 3n + 3
Step-by-step explanation:
The sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
From the recursive formula
a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then
= 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3