Help! I can't figure this out!

Mathematics

1 answer:

Vanyuwa [196]2 years ago

6 0

Answer:

57/6 60/6 22/6 26/6

Step-by-step explanation:

So the answers for the blanks are 57, 60, 22, 26.

Let me know if I am incorrect.

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Drupady [299]

I believe it’s C. 3/2

5 0

2 years ago

Write the inverse of h(x) = e 2x h -1(x) = log e2 x 2log ex ½log ex

svp [43]

Answer:

Step-by-step explanation:

So we have the function:

$h(x)=e^{2x}$

To find the inverse, switch h(x) and x, change h(x) to h⁻¹(x), and solve for it. Thus: "

$x=e^{2h^{-1}(x)}$

So, take the natural log (log to base e) of both sides:

$\ln(x)=\ln(e^{2h^{-1}(x)})$

The right side will cancel:

$\ln(x)=2h^{-1}(x)$

Divide both sides by 2:

$h^{-1}(x)=\frac{1}{2}\ln(x)$

And we're done!

Our answer is C

Note:

$\ln(x)=\log_ex$

6 0

3 years ago

If a perimeter is 20/21 what is the side length of the square

Sever21 [200]

Answer:

each side would be 5/21

6 0

3 years ago

Read 2 more answers

Determine the sum of the first 9 terms in the geometric series where r= -0.25 and a1= 256.

Damm [24]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ r=-0.25\\ a_1=256\\ n=9 \end{cases}$

$\bf S_9=256\left(\cfrac{1-(-0.25)^9}{1-(-0.25)} \right)\implies S_9=256\left( \cfrac{1+0.25^9}{1+0.25} \right) \\\\\\ S_9=256\left( \cfrac{52429}{65536}\right)\implies S_9=\cfrac{52429}{256}\implies S_9=204.80078125$